Question

The average of 10 numbers is −10. If the sum of 6 of them is 100, what is the average of the other 4? 20pts

Answer 1

Answer:

The sum of the other 4 numbers is $-200$

Step-by-step explanation:

Let

x------> the sum of 6 numbers

y-----> the sum of the other 4 numbers

we know that

$\frac{x+y}{10}=-10$ -----> equation A

$x=100$

substitute the value of x in the equation A

$\frac{100+y}{10}=-10$

$\frac{100}{10}+\frac{y}{10}=-10$

$10+\frac{y}{10}=-10$

$\frac{y}{10}=-10-10$

$\frac{y}{10}=-20$

$y=-20*10=-200$

Answer 2

Answer:

-50

Step-by-step explanation:

if the average of the 10 numbers is -10, that means the sum will be -10*10 or -100.

the sum of 6 numbers is 100

Then the sum of the 4 numbers would be  (-100-100) or -200

From that we count the average to be -200/4 or -50