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maria [59]
3 years ago
12

(a) use the pythagorean theorem to determine the length of the unknown side of the triangle, (b) determine the perimeter of the

triangle, and (c) determine the area of the triangle. the figure is not drawn to scale.
a. the length of the unknown side is ___

b. the perimeter of the triangle is ___

c. the area of the triangle is ___

Mathematics
1 answer:
Kisachek [45]3 years ago
8 0

Answer:

(A) 40 km

(B) 90 km

(C) 180 km²

Step-by-step explanation:

To find the missing side of this triangle, let's use the Pythagorean theorem.

a^2+b^2=c^2, assuming that a and b are legs, and c is the hypotenuse.

Assuming the 9km side is a, we need to find the value of b, so we can substitute into the equation.

9^2+b^2=41^2\\81+b^2=1681\\b^2=1681-81\\b^2=1600\\\\b = \sqrt{1600} \\b=40

So, the length of the missing side is 40. Now that we know this piece of information, we can find the perimeter and area of the triangle.

The perimeter is all the sides added together, so 41+9+40 = 90 km is the perimeter.

The area are the two legs multiplied divided by 2.

So,

\frac{9\cdot40}{2} \\\\\frac{360}{2}\\\\180

So the area of this triangle is 180 cm²

I hope this helped!

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How many liters is 250,000 cm3?
eimsori [14]
Once cubic centimeter = 1 milleter

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3 years ago
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8x+5y=35 solve for y no work needed but you can show me the work if you want i will still look at it thank you in advance
solong [7]

Answer:

y=7-(8/5)x

Step-by-step explanation:

To solve for y we need to get Y on one side of the equation all by itself.  To start we can move the 8x to the side with the 35 by subtracting 8x on both sides which gets us to 5y=35-8x then we just need to get the 5 detached from the y and we will have solved for Y.  To do this we can divide by 5 on both sides to cancel out the 5 with the Y which leaves us with y=7-(8/5)x

I hope this helps and please don't hesitate to ask if there is anything still unclear!

4 0
3 years ago
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Seven cards are drawn from an ordinary deck. In how many ways is it possible to draw ​(b) only 8​'s, ​'s and ​(c) no ​'s, ​'s an
elena-14-01-66 [18.8K]

Complete question :

Seven cards are drawn from an ordinary deck. In how mnat ways is it possible to draw (a) only 5s (b)only 8s, 9s, and 10s, (c) no 8s, 9s, and 10s (d) exactly 2 jacks or kings, (e) 5 spades and 2 hearts?

Answer:

0; 792 ; 100396 ; 30408224 ; 18643560 ;

Step-by-step explanation:

Number of cards in a deck = 52

Number of cards to be drawn = 7

Using combination:

nCr = n! ÷ (n-r)!r!

A.)

Number of 5's in a deck = 4

4C7 = 0

(B.)

only 8s, 9s, and 10s,

Number of 8, 9 and 10's = 4 *3 = 12

12C7 = 12! ÷ 5!7! = 792

(C)

no 8s, 9s, and 10s ;

Number of cards to select from = 52 - (3(4)) = 40C7 = 18643560

(D)

exactly 2 jacks or kings,

Number of jack or king in deck = 8 ; other 5 could be any of the rest : (52 - 8) = 44

8C2 * 44C5 = 28 * 1086008 = 30408224

(e) 5 spades and 2 hearts?

Number of spades = 13

Number of hearts = 13

13C5 * 13C2

1287 * 78 = 100396

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armand deposited $389.42 in a savings account that earns 3.2% simple interest. what is armand’s account balance after 7 years?
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Okay so since we have $389.42 to start with, we will multiply that by 3.2% which gives us roughly $12.46. Knowing that he will get an additional $12.46 per year, we multiply 12.46 by 7, giving us $87.22. Now, we just add 87.22 to 389.42, which is 476.64. Therefore, Armand has $476.64 as his account after 7 years.

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