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slamgirl [31]
2 years ago
11

Im not sure how to do this question

Mathematics
2 answers:
SOVA2 [1]2 years ago
5 0
#2)the correct choice is D
#3)choice B is the correct answer
Pavel [41]2 years ago
3 0
B. -9 is the most negative one, -2 is the least.
Hope this helps you.
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Which statement about the slope of a line is true?
Fudgin [204]

Answer:

B) A line with a positive slope increases as it is viewed from left to right.

Step-by-step explanation:

A line with a positive slope increases as it is viewed from left to right.

A positive slope means that as a line on the line graph moves from left to right, the line rises.

Hope this helps :)

8 0
2 years ago
WILL GIVE BRAINLIEST
Maru [420]

Answer:

sry man

Step-by-step explanation:

8 0
2 years ago
Question 2 help please
m_a_m_a [10]

Answer:

The measure of the vertex angle is 94 degrees ⇒ A

Step-by-step explanation:

  • In any triangle, the sum of the measures of its interior angle is 180°
  • In the isosceles triangle, the two base angles are equal in measures

∵ In an isosceles triangle, the measure of the base angle = (2x + 5)

∵ The base angles of the isosceles triangles are equal in measures

∴ The measures of the base angles are (2x + 5), (2x + 5)

∵ The measure of the vertex angle = (5x - 1)

∵ The sum of the measure of the three angles = 180°

∴ (2x + 5) + (2x + 5) + (5x - 1) = 180

→ Add the like terms in the left side

∵ (2x + 2x + 5x) + (5 + 5 + -1) = 180

∴ 9x + 9 = 180

→ Subtract 9 from both sides

∴ 9x + 9 - 9 = 180 - 9

∴ 9x = 171

→ Divide both sides by 9 to find x

∴ x = 19

→ Substitute the value of x in the measure of the vertex angle to find it

∵ The measure of the vertex angle = 5x - 1

∴ The measure of the vertex angle = 5(19) - 1

∴ The measure of the vertex angle = 95 - 1

∴ The measure of the vertex angle = 94°

∴ The measure of the vertex angle is 94 degrees

6 0
3 years ago
Suppose we have a population whose proportion of items with the desired attribute is p = 0:5. (a) If a sample of size 200 is tak
crimeas [40]

Answer:

a. If a sample of size 200 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 41.26%.

b. If a sample of size 100 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 30.5%.

Step-by-step explanation:

This problem should be solved with a binomial distribution sample, but as the size of the sample is large, it can be approximated to a normal distribution.

The parameters for the normal distribution will be

\mu=p=0.5\\\\\sigma=\sqrt{p(1-p)/n} =\sqrt{0.5*0.5/200}= 0.0353

We can calculate the z values for x1=0.47 and x2=0.51:

z_1=\frac{x_1-\mu}{\sigma}=\frac{0.47-0.5}{0.0353}=-0.85\\\\z_2=\frac{x_2-\mu}{\sigma}=\frac{0.51-0.5}{0.0353}=0.28

We can now calculate the probabilities:

P(0.47

If a sample of size 200 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 41.26%.

b) If the sample size change, the standard deviation of the normal distribution changes:

\mu=p=0.5\\\\\sigma=\sqrt{p(1-p)/n} =\sqrt{0.5*0.5/100}= 0.05

We can calculate the z values for x1=0.47 and x2=0.51:

z_1=\frac{x_1-\mu}{\sigma}=\frac{0.47-0.5}{0.05}=-0.6\\\\z_2=\frac{x_2-\mu}{\sigma}=\frac{0.51-0.5}{0.05}=0.2

We can now calculate the probabilities:

P(0.47

If a sample of size 100 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 30.5%.

8 0
3 years ago
Greg is trying to solve a puzzle where he has to figure out two numbers, x and y. Three less than two-third of x is greater than
Fittoniya [83]
Inequation 1: 

\frac{2}{3}x-3 \geq y

to plot the pairs (x, y) for which the inequation holds, draw the line y=\frac{2}{3}x-3

then pick a point in either side of the line. If that point is a solution of the inequation, than color that region of the line, if that point is not a solution, then color the other part of the line.

we do the same for the second inequation. Then the solution, is the region of the x-y axes colored in both cases.

inequation 2: 

y+ \frac{2}{3}x\ \textless \ 4

y\ \textless \ - \frac{2}{3} x+ 4



draw the lines 

i)  y=\frac{2}{3}x-3          use points (0, -3),  (3, -1)

ii)y=- \frac{2}{3} x+ 4       use points ( 0, 4),   (3, 2)


let's use the point P(3, 3) to see what region of the lines need to be coloured:

\frac{2}{3}x-3 \geq y  ; 
\frac{2}{3}(3)-3 \geq 3
2-3 \geq 3, not true so we color the region not containing this point


y+ \frac{2}{3}x\ \textless \ 4
(3)+ \frac{2}{3}(3)\ \textless \ 4
3+ 5\ \textless \ 4 not true, so we color the region not containing the point (3, 3)

The graph representing the system of inequalities is the region colored both red and blue, with the blue line not dashed, and the red line dashed.



4 0
3 years ago
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