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loris [4]
3 years ago
8

For a bingo game, wooden balls are numbered consecutively from 1 to 75 are placed in a box. five balls are drawn at random. find

the probability of selecting 5 even numbers
Mathematics
1 answer:
MariettaO [177]3 years ago
6 0
37 out of 75. That's just about it
You might be interested in
A jar holds no more than 500 buttons. If 5 people bring 330 buttons each, how many jars are necessary to hold all of the buttons
Strike441 [17]

Answer:

We know

1 jar = 500 buttons

5 people bring 330 buttons EACH

We can find/solve by...

people x buttons = total buttons

total buttons / 500 = number of jars needed

So..

5 x 330 = 1650

1650 / 500 = 3.3

Your answer:

4 jars

Explanation

It's impossible to have 3.3 jars, so you must round up.

Step-by-step explanation:

8 0
3 years ago
Simplify (7x2 - 2x + 9) + (3x2 + 15x – 4).
VikaD [51]

Hey! Your answer for this is

7x^2 + 3x^2 = 10x^2

-2x + 15x = 13x

9 - 4 = 5

Hence, 10x^2 + 13x + 5.

Hope this helps!

5 0
4 years ago
Read 2 more answers
HURRRRRRRRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
Viefleur [7K]

Answer:

41*

Step-by-step explanation:

90*-41*=41*

Hope This Helps;)<3

6 0
3 years ago
Read 2 more answers
The U.S. Bureau of Economic Statistics reports that the average annual salary in the metropolitan Boston area is $50,542. Suppos
xenn [34]

Answer:

(a) P(X > $57,000) = 0.0643

(b) P(X < $46,000) = 0.1423

(c) P(X > $40,000) = 0.0066

(d) P($45,000 < X < $54,000) = 0.6959

Step-by-step explanation:

We are given that U.S. Bureau of Economic Statistics reports that the average annual salary in the metropolitan Boston area is $50,542.

Suppose annual salaries in the metropolitan Boston area are normally distributed with a standard deviation of $4,246.

<em>Let X = annual salaries in the metropolitan Boston area</em>

SO, X ~ Normal(\mu=$50,542,\sigma^{2} = $4,246^{2})

The z-score probability distribution for normal distribution is given by;

                      Z  =  \frac{X-\mu}{\sigma }  ~ N(0,1)

where, \mu = average annual salary in the Boston area = $50,542

            \sigma = standard deviation = $4,246

(a) Probability that the worker’s annual salary is more than $57,000 is given by = P(X > $57,000)

    P(X > $57,000) = P( \frac{X-\mu}{\sigma } > \frac{57,000-50,542}{4,246 } ) = P(Z > 1.52) = 1 - P(Z \leq 1.52)

                                                                     = 1 - 0.93574 = <u>0.0643</u>

<em>The above probability is calculated by looking at the value of x = 1.52 in the z table which gave an area of 0.93574</em>.

(b) Probability that the worker’s annual salary is less than $46,000 is given by = P(X < $46,000)

    P(X < $46,000) = P( \frac{X-\mu}{\sigma } < \frac{46,000-50,542}{4,246 } ) = P(Z < -1.07) = 1 - P(Z \leq 1.07)

                                                                     = 1 - 0.85769 = <u>0.1423</u>

<em>The above probability is calculated by looking at the value of x = 1.07 in the z table which gave an area of 0.85769</em>.

(c) Probability that the worker’s annual salary is more than $40,000 is given by = P(X > $40,000)

    P(X > $40,000) = P( \frac{X-\mu}{\sigma } > \frac{40,000-50,542}{4,246 } ) = P(Z > -2.48) = P(Z < 2.48)

                                                                     = 1 - 0.99343 = <u>0.0066</u>

<em>The above probability is calculated by looking at the value of x = 2.48 in the z table which gave an area of 0.99343</em>.

(d) Probability that the worker’s annual salary is between $45,000 and $54,000 is given by = P($45,000 < X < $54,000)

    P($45,000 < X < $54,000) = P(X < $54,000) - P(X \leq $45,000)

    P(X < $54,000) = P( \frac{X-\mu}{\sigma } < \frac{54,000-50,542}{4,246 } ) = P(Z < 0.81) = 0.79103

    P(X \leq $45,000) = P( \frac{X-\mu}{\sigma } \leq \frac{45,000-50,542}{4,246 } ) = P(Z \leq -1.31) = 1 - P(Z < 1.31)

                                                                      = 1 - 0.90490 = 0.0951

<em>The above probability is calculated by looking at the value of x = 0.81 and x = 1.31 in the z table which gave an area of 0.79103 and 0.9049 respectively</em>.

Therefore, P($45,000 < X < $54,000) = 0.79103 - 0.0951 = <u>0.6959</u>

3 0
3 years ago
There are 3,072 books in the school library. There are 96 sixth graders. If the sixth graders teamed up to read all the books, h
Semenov [28]
The only thing you should do is to divide 3,072 by 96 and the answer is 32.
So each of them should read 32 books :)))
I hope this is helpful
have a nice day
7 0
3 years ago
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