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Softa [21]
3 years ago
8

Find the distance between the points. (-3,5) and (1,5)

Mathematics
2 answers:
Ksju [112]3 years ago
8 0

Answer:

4 units

Step-by-step explanation:

Citrus2011 [14]3 years ago
8 0

Answer:

4 units

Step-by-step explanation:

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Can somebody explain to me stem and leaf diagrams please?
aev [14]
They are a method for showing the frequency of a data plot in a much more compact and numerical way.  

1[2 3
2[1 7
3[3 4 5 7 
4[ 0 0 1

Key 1[2= 12

meaning that 3[5 is 35 and 4[0 is 40 and so and so forth
5 0
3 years ago
Slove for P. 5/7=p+4/7
Sever21 [200]
p= 1/7
Alright, so first, you need to flip the equation.<span><span>It will turn into p+<span>4/7</span></span>=<span>5/7
Next, you want to get the variable by itself so you need to subtract 4/7 from both sides. 5/7-4/7=1/7
p=1/7</span></span>
5 0
3 years ago
Determine whether the given vectors are orthogonal, parallel or neither. (a) u=[-3,9,6], v=[4,-12,-8,], (b) u=[1,-1,2] v=[2,-1,1
nevsk [136]

Answer:

a) u v= (-3)*(4) + (9)*(-12)+ (6)*(-8)=-168

Since the dot product is not equal to zero then the two vectors are not orthogonal.

|u|= \sqrt{(-3)^2 +(9)^2 +(6)^2}=\sqrt{126}

|v| =\sqrt{(4)^2 +(-12)^2 +(-8)^2}=\sqrt{224}

cos \theta = \frac{uv}{|u| |v|}

\theta = cos^{-1} (\frac{uv}{|u| |v|})

If we replace we got:

\theta = cos^{-1} (\frac{-168}{\sqrt{126} \sqrt{224}})=cos^{-1} (-1) = \pi

Since the angle between the two vectors is 180 degrees we can conclude that are parallel

b) u v= (1)*(2) + (-1)*(-1)+ (2)*(1)=5

|u|= \sqrt{(1)^2 +(-1)^2 +(2)^2}=\sqrt{6}

|v| =\sqrt{(2)^2 +(-1)^2 +(1)^2}=\sqrt{6}

cos \theta = \frac{uv}{|u| |v|}

\theta = cos^{-1} (\frac{uv}{|u| |v|})

\theta = cos^{-1} (\frac{5}{\sqrt{6} \sqrt{6}})=cos^{-1} (\frac{5}{6}) = 33.557

Since the angle between the two vectors is not 0 or 180 degrees we can conclude that are either.

c) u v= (a)*(-b) + (b)*(a)+ (c)*(0)=-ab +ba +0 = -ab+ab =0

Since the dot product is equal to zero then the two vectors are orthogonal.

Step-by-step explanation:

For each case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

Part a

u=[-3,9,6], v=[4,-12,-8,]

The dot product on this case is:

u v= (-3)*(4) + (9)*(-12)+ (6)*(-8)=-168

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|u|= \sqrt{(-3)^2 +(9)^2 +(6)^2}=\sqrt{126}

|v| =\sqrt{(4)^2 +(-12)^2 +(-8)^2}=\sqrt{224}

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{uv}{|u| |v|}

And the angle is given by:

\theta = cos^{-1} (\frac{uv}{|u| |v|})

If we replace we got:

\theta = cos^{-1} (\frac{-168}{\sqrt{126} \sqrt{224}})=cos^{-1} (-1) = \pi

Since the angle between the two vectors is 180 degrees we can conclude that are parallel

Part b

u=[1,-1,2] v=[2,-1,1]

The dot product on this case is:

u v= (1)*(2) + (-1)*(-1)+ (2)*(1)=5

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|u|= \sqrt{(1)^2 +(-1)^2 +(2)^2}=\sqrt{6}

|v| =\sqrt{(2)^2 +(-1)^2 +(1)^2}=\sqrt{6}

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{uv}{|u| |v|}

And the angle is given by:

\theta = cos^{-1} (\frac{uv}{|u| |v|})

If we replace we got:

\theta = cos^{-1} (\frac{5}{\sqrt{6} \sqrt{6}})=cos^{-1} (\frac{5}{6}) = 33.557

Since the angle between the two vectors is not 0 or 180 degrees we can conclude that are either.

Part c

u=[a,b,c] v=[-b,a,0]

The dot product on this case is:

u v= (a)*(-b) + (b)*(a)+ (c)*(0)=-ab +ba +0 = -ab+ab =0

Since the dot product is equal to zero then the two vectors are orthogonal.

5 0
4 years ago
Read 2 more answers
Joe paid $14 for a board game. this is 70% of the original price. what was the original price?
tino4ka555 [31]

Step-by-step explanation:

It is given that Joe paid 14.00 for a board game this is 70% of the original price what is the original price.

Let the original price of board game be

X.

x * 70/100 = 14

x * 7/10 = 14

Multiply both sides by 10.

7x = 140

Divide both sides by 7.

x = 20

4 0
2 years ago
Here is another one I need help with​
aksik [14]

Answer:

Step-by-step explanation:

Surface area of objects with flat surfaces like this is simply the area of each surface added together, so let's get to work.

Both have 6 faces, so we will be adding six values together for each.

Container A:

Hopefully you can imagine the six different faces.  It's kinda like a cereal box.

The front and back of a cereal box have the same area, as do the two sides and the top and bottom, so that makes it a little easier.

Front and Back:  28 * 36 = 1008

Sides: 36*6 = 216

Top and Bottom: 6*28 = 168

Let me know if you don't understand how I did any of that.  Anyway, since there is a matching face for each we add them all together twice.  

1008*2 + 216*2 + 168*2 = 2784 in^2

Container B has a similar setup, I won't write out everything like I did unless you want me to work it out with you.

2(16*12+16*22+22*12) = 1616 in^2

So since Container A has a surface area of 2784 and Container B has a surface area of 1616 it's obvious container A has a larger surface area

4 0
3 years ago
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