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2 years ago

Is it linear or nonlinear

Mathematics

2 answers:

Lerok [7]2 years ago

6 0

Answer:

linear

Step-by-step explanation:

Paraphin [41]2 years ago

3 0

I believe it’s linear

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Parallelograms ABDC and EFHG are similar. If side AC equals 4 units, side AB equals 16 units, and side EG equals 32 units, what

alexdok [17]

Remember that sides AC and EG will correspond. By finding the ratio of the lengths of these sides, we can find the length of EF.
The ratio of 4 to 16 simplifies to 1:4. This means that every side in ABDC is 1/4th of its corresponding side in EFHG. 16 times 4 is 64, so EF has a length of 64 units.

4 0

2 years ago

I need the complete answer to this problem, please circle the final answer and what I should write

goblinko [34]

Answer:

$f(t) = 8400(1.0018)^{12t}$

2.22%

Step-by-step explanation:

$8400 is invested in an account earning 2.2% interest (APR), compounded monthly.

So, the value of the account after t years will be given by

$f(t) = 8400 (1 + \frac{2.2}{12 \times 100} )^{12t} = 8400(1.0018)^{12t}$ {Rounded to the four decimal places} (Answer)

Now, for t = 1 year, f(1) = $8586.67

So, the percentage of growth per year (APY) = $\frac{(8586.67 - 8400) \times 100}{8400} = 2.22$ % {Rounded to the nearest hundredth of percent} (Answer)

5 0

2 years ago

(1,-7) with a slope of -5 as an equation

Liono4ka [1.6K]

Answer:

y=-5x-2

Step-by-step explanation:

y=mx+b

where m is the slope

y=-5x+b

to solve for b, which is the y intercept, plug in (1,-7)

-7=-5(1)+b

-7=-5+b

-2=b

y=-5x-2

7 0

2 years ago

Name the set(s) of numbers to which -10 belongs.

NeX [460]

-10 belongs to integers, rational numbers, and real numbers.

6 0

2 years ago

Read 2 more answers

How do you solve this

AlladinOne [14]

Answer:

domain: all terms are defined for <em>all real numbers</em>
solution: x = 6

Step-by-step explanation:

Rewrite the equation as a single exponential. After taking the log, the solution becomes obvious.

$5^{x-2}-7^{x-3}=7^{x-5}+11\cdot 5^{x-4}\\\\5^{x-2}-11\cdot 5^{x-4}=7^{x-3}+7^{x-5}\\\\5^{x-2}(1-11\cdot 5^{-2})=7^{x-3}(1+7^{-2})\\\\5^{x-2}\dfrac{14}{25}=7^{x-3}\dfrac{50}{49}\\\\1=\dfrac{2\cdot 7^{x-3}5^4}{2\cdot 5^{x-2}7^3}=\left(\dfrac{7}{5}\right)^{x-6}\\\\0=(x-6)\log(1.4)\\\\x=6$

6 0

2 years ago