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dalvyx [7]
3 years ago
14

Plz help !!!!! Will mark brainliest

Mathematics
2 answers:
mel-nik [20]3 years ago
5 0

Answer:

B

Step-by-step explanation:

1) divide -21/-6 which gives you 7/2

2) Since v are both the same bases we can subtract to 6-8 = -2

3) A negative goes to the denominator. Therefore, it’s B

cricket20 [7]3 years ago
3 0
I think it’s going to be B.
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each of the 20 balls is tossed independently and at random into one of the 5 bins. let p be the probability that some bin ends u
amm1812

if p is the probability that some bin ends up with 3 balls and q is the probability that every bin ends up with 4 balls. pq is 16.

First, let us label the bins with 1,2,3,4,5.

Applying multinomial distribution with parameters  n=20  and  p1=p2=p3=p4=p5=15  we find that probability that bin1 ends up with 3, bin2 with 5 and bin3, bin4 and bin5 with 4 balls equals:

5−2020!3!5!4!4!4!

But of course, there are more possibilities for the same division  (3,5,4,4,4)  and to get the probability that one of the bins contains 3, another 5, et cetera we must multiply with the number of quintuples that has one 3, one 5, and three 4's. This leads to the following:

p=20×5−2020!3!5!4!4!4!

In a similar way we find:

q=1×5−2020!4!4!4!4!4!

So:

pq=20×4!4!4!4!4!3!5!4!4!4!=20×45=16

thus, pq = 16.

To learn more about Probability visit: brainly.com/question/29508225

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7 0
1 year ago
Instructions: Use the ratio of a 30-60-90 triangle to solve for the variables.
Pepsi [2]

Answer:

x=20

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Step-by-step explanation:

In the triangle we have the following trigonometric equations:

tan(60^o)=\frac{opposite}{adjacent} \\\sqrt{3} =\frac{y}{10} \\y=10\,\sqrt{3}

and also:

cos(60^o)=\frac{adjacent}{hypotenuse}\\\frac{1}{2} =\frac{10}{x}\\x=20

8 0
3 years ago
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fredd [130]

Answer:

the absolute value of 32 ( |32| ) is 32

Step-by-step explanation:

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hope this helps!

3 0
3 years ago
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Yakvenalex [24]
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3 years ago
Find the product in its simplest form<br><br> 2/5 * 3/7
Mamont248 [21]

Answer:

6/35

Step-by-step explanation:

I just used my calculator...

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2 years ago
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