Answer:
11.3353
Step-by-step explanation:
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Answer:
Below in bold.
Step-by-step explanation:
1) ( a^2 + b^2 = (a + b)^2 - 2ab
= 29 - 2(6)
= 29-12
= 17.
2). (x - y)^2 = x^2 + y^2 - 2xy
so 20 = 18 - 2xy
2xy = 18-20 = -2
xy = -1.
3). 1/x + x = 7
(1/ x + x)^2 = 1/x^2 + x^2 +x/x + x/x
= 1/x^2 + x^2 + 2
But(1/x + x)^2 = 7^2 = 49
so 1/x^2 + x^2 + 2 = 49
so 1/x^2 + x^2 = 49 - 2 = 47.
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Answer:
Step-by-step explanation:
Given that
AB n GF = O
E ∈ ∠GOB
H ∈ ∠AOF
The we can say, using similar angles or triangles, that
BF = AG
EG = AH
BG = FA
Answer:
The discriminant of ax^2+bx+c is b^2-4ac.
If the discriminant, d, is:
d<0, there are no real solutions (there are two imaginary solutions however)
d=0, there is one real solution
d>0, there are two real solutions
In this case d=16-32=-16 so there are two imaginary solutions. Or from your answer choices, it can be said that there are no real number solutions becuse the discriminant is less than zero.
