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Stells [14]
3 years ago
6

 PLZ HELP EASY PLZ HELP ME Two vertices of a right triangle have the coordinates (−2, 5) and (9, 5) .

Mathematics
2 answers:
Sever21 [200]3 years ago
6 0
I say its 11. Since the distance between the two points is 11. 

ivann1987 [24]3 years ago
3 0

Answer:


Step-by-step explanation:


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Which equation has the components of 0 = x2 – 9x – 20 inserted into the quadratic formula correctly?
Aneli [31]

Answer:

The required equation is x=\frac{-(-9)\pm \sqrt{(-9)^2-4(1)(-20)}}{2(1)}.

Step-by-step explanation:

If a quadratic equation is ax^2+bx+c=0, then the quadratic formula is

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

The given quadratic equation is

x^2-9x-20=0

Here, a=1, b=-9 and c=-20.

Substitute a=1, b=-9 and c=-20 in the above quadratic formula.

x=\frac{-(-9)\pm \sqrt{(-9)^2-4(1)(-20)}}{2(1)}

Therefore the required equation is x=\frac{-(-9)\pm \sqrt{(-9)^2-4(1)(-20)}}{2(1)}.

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drek231 [11]

Answer:

Hello your question is incomplete attached below is the complete question

answer :  1596 ± 2.861 \sqrt{\frac{1580^2 }{20 } +\frac{2350^2 }{20 } } ------  ( A )

Step-by-step explanation:

I will use excel function to resolve this question

<u>Determine the 99% confidence of interval for the difference in mean  number of steps by all people</u>

∝ = 0.01

critical value ( t ) = 2.861  ( = TINV ( 0.01, 19 )

Given that :

S1 = 1580

S2 = 2350

n1 = 20

n2 = 20

Difference in mean = x1 - x2 = 1596

Margin of Error = t * \sqrt{\frac{S^2_{1} }{n_{1} } +\frac{s^2_{2} }{n_{2} } }

∴  99% confidence of interval

= 1596 ± 2.861 \sqrt{\frac{1580^2 }{20 } +\frac{2350^2 }{20 } } ------

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