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Anastasy [175]
3 years ago
5

The solution set of this inequality? 11q+5≤49

Mathematics
2 answers:
sineoko [7]3 years ago
3 0

Subtract 5 from both sides.

49 - 5 = 44

11q ≤ 44

Divide both sides by 11.

44/11 = 4

q ≤ 4

Dvinal [7]3 years ago
3 0
<h2>Answer:</h2>

<u>The answer is</u><u> q ≤ 4</u>

<h2>Step-by-step explanation:</h2>

11q+5 ≤ 49

Subtracting 5 from both sides

11q ≤ 49 - 5

11q ≤ 44

Dividing both sides by 11

q ≤ 4

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The 1984 movie footloose made $8,556,965 in its opening weekend. The 2011 remake of footloose made $15,556,113 in its opening we
mezya [45]

Answer:

  • absolute change: $6,999,148
  • relative change: 81.79%

Step-by-step explanation:

The absolute change is the difference between the earnings numbers:

  $15,556,113 -8,556,965 = $6,999,148

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The relative change is the ratio of this difference to the original amount:

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6 0
3 years ago
Need help on this question for math
KATRIN_1 [288]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
Ve. .
Alinara [238K]

Answer:

They are (6, 1) or (3, 2).

Step-by-step explanation:

The factor pairs of 6 are 1×6 and 2×3

So the parallelogram (height by length) could be:

1 by 6

2 by 3

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3 0
3 years ago
Three six-sided fair dice are rolled. The six sides of each die are numbered 1; 2; : : : ; 6. Let A be the event that the first
valkas [14]

Answer:

1.) [A, B, C]

2.) [A', B', C']

3.) [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

4.) A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

Step-by-step explanation:

If A is the event that the first die shows an even number, then A' is the event that first die DOES NOT show an even number.

If B is the event that the Second die shows and even number, then B' is the event that second die DOES NOT show an even number.

If C is the event that the third die shows an even number, then C' is the event that third die DOES NOT show an even number.

Hence, our possible events are A, A', B, B', C, C'.

For question 1, in the event that all three dice show and even number, the expression of the event = [A, B, C]

For question two, in the event that no die shows an even number, the expression of the event = [A', B', C']

For question 3,In the event that at least one die shows an odd number, the expression of the event = [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

For question 4,in the event that at most two dice show odd numbers, the expression of the event = [A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

6 0
3 years ago
Help me pls !!!!!!!!!!
Levart [38]

Answer:

c and d

Step-by-step explanation:

6 0
3 years ago
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