You move the decimal point forward until it reaches the one so it looks like this:
1.4 x 10⁵
the exponent, 5, just tells you how many spaces the decimal point moved.
First arrange numbers
14,15,15,17,19,20,21,23,24
19 is median
15+15/2=15 is first quartile
use the Pythagoras theorem method
a squared plus b squared equals c square
Answer:
193 mg
Step-by-step explanation:
Exponential decay formula:
- where Aₜ = mass at time t, A₀ = mass at time 0, r = decay constant (rate), t = time
Our known variables are:
- 1998 to the year 2004 is a total of t = 6 years.
- The sample of radioactive isotope has an initial mass of A₀ = 360 mg at time 0 and a mass of Aₜ = 270 mg at time t.
Let's solve for the decay constant of this sample.
Using our new variables, we can now solve for Aₜ at t = 7 years, since we go from 2004 to 2011.
Our new initial mass is A₀ = 270 mg. We solved for the decay constant, r = 0.04794701.
The expected mass of the sample in the year 2011 would be 193 mg.
Answer:
Option C. x + 12 ≤ 2(x – 3)
Step-by-step explanation:
From the question, we obtained the following information:
x + 12 ≤ 5 – y .......(1)
5 – y ≤ 2(x – 3) ....... (2)
To know which option is correct, do the following:
From equation 2,
5 – y ≤ 2(x – 3)
Thus, we can say
5 – y = 2(x – 3)
Now, we shall substitute the value of 5 – y into equation 1 as shown below:
x + 12 ≤ 5 – y
5 – y = 2(x – 3)
x + 12 ≤ 2(x – 3)
From the above illustration, we can see that if x + 12 ≤ 5 – y and 5 – y ≤ 2(x – 3), then x + 12 ≤ 2(x – 3) must be true.
Option C gives the correct answer.
