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3 years ago

Hello peepers! I need help ASAP please. Thanks!

1 answer:

6 0

The answer would be C because you are subtracting 3 by a number(x) because you are REMOVING garbage. And if you remove the x from 3x and replace it with the number of weeks, you'll get the number of loads dumped. For example -3(5)+60. Follow your order of operations. Multiply first to get -15. Then add that to 60. You will get 45, which is the correct answer because in the problem, the number of loads are 45. Or how about this, -3(10)+60. Multiply first to get -30, then add positive 60 to get 30 overall. Since 30 is the number of loads removed in the problem, your answer is correct, thus, making the correct equation C.

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What are the zeros of the function y = 2x2 +9x+4 ?

guajiro [1.7K]

Answer:

I think no A. x = -1/2 ,x = -4

8 0

3 years ago

Pip and Sara win some money and share it in ratio 5:4 pip gets £50 how much did they get all together

N76 [4]

Answer: £90

Step-by-step explanation:

Pip and Sara get some money. They share it in the ratio 5 : 4.

Pip gets £50 so what did Sara get:

Use direct proportion:

5 : 4

50 : x

5x = 200

x = 200/5

x = £40

Pip got £50 and Sara got £40.

Together they got:

= 50 + 40

= £90

4 0

3 years ago

Match its group with its percentage or mean Using

krok68 [10]

(1)

Mean length of all fish in the sample - $\boxed{\sf{\red{6.2}}}$

Mean = (Sum of observations)/(Number of observations)

= (12 + 5 + 3 + 5 + 8 + 2 + 10 + 9 + 4 + 4)/(10)

= 62/10

= 6.2

(2)

Mean length of adult fish in the sample - $\boxed{\sf{\red{8.75}}}$

Mean = (Sum of observations)/(Number of observations)

= (12 + 5 + 8 + 10)/(4)

= 35/4

= 8.75

(3)

Mean length of juvenile fish in the sample - $\boxed{\sf{\red{4.5}}}$

Mean = (Sum of observations)/(Number of observations)

= (5 + 3 + 2 + 9 + 4 + 4)/(6)

= 27/6

= 4.5

(4)

Percentage of sample that were adult fish - $\boxed{\sf{\red{40}}}$

Percentage = (No. of adult fishes)/(Total no. of fishes) × 100

% = (4/10) × 100

% = 40

(5)

Percentage of sample that were juvenile fish - $\boxed{\sf{\red{60}}}$

Percentage = (No. of juvenile fishes)/(Total no. of fishes) × 100

% = (6/10) × 100

% = 60

(6)

Percentage of sample that were juveniles over 8 inches long - $\boxed{\sf{\red{10}}}$

Percentage = (No. of juveniles over 8 inches)/(Total no. of fishes) × 100

% = (1/10) × 100

% = 10

7 0

3 years ago

ANSWER ASAP

Nadusha1986 [10]

Y=mx+b
m=0.5
b is value of y in y-intercept, b=-2

The equation of this line is
y=0.5x-2

When x=4
y=0.5x-2=y=0.5*4-2=2-2 = 0
When x=4, y=0.

6 0

3 years ago

5{-3.4k-7} + {3k+21}

lina2011 [118]

The answer is −14k−14. Hope this helps.

8 0

3 years ago