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Andreyy89
3 years ago
11

Hello peepers! I need help ASAP please. Thanks!

Mathematics
1 answer:
aivan3 [116]3 years ago
6 0
<span>The answer would be C because you are subtracting 3 by a number(x) because you are REMOVING garbage. And if you remove the x from 3x and replace it with the number of weeks, you'll get the number of loads dumped. For example -3(5)+60. Follow your order of operations. Multiply first to get -15. Then add that to 60. You will get 45, which is the correct answer because in the problem, the number of loads are 45. Or how about this, -3(10)+60. Multiply first to get -30, then add positive 60 to get 30 overall. Since 30 is the number of loads removed in the problem, your answer is correct, thus, making the correct equation C.</span>
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Which relationship is not a function 10 POINTS
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top left

Step-by-step explanation:

take a vertical line and place it on the graph. Then no matter where on the graph you place the vertical line, the graph should only cross the vertical line once. ( it only crossed once)

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2 Amount of stretching

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What type of proportion is shown in 12 : 4 = 24 : 8?​
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This problem has been solved!See the answerA municipal bond service has three rating categories (A, B, and C). Suppose that in t
mariarad [96]

Answer:

a. \frac{35}{51}

b. \frac{51}{100}

c. \frac{1}{5}

Step-by-step explanation:

Suppose cities represented by C', suburbs represented by S and rural represented by R,

Let x be the total number of bonds issued throughout the US,

According to the question,

n(A) = 70% of x = 0.7x,

n(B) = 10% of x = 0.1x,

n(C) = 20% of x = 0.2x,

n(A∩C') = 50% of n(A) = 0.5 × 0.7x = 0.35x,

n(A∩S) = 20% of n(A) = 0.2 × 0.7x = 0.14x,

n(A∩R) = 30% of n(A) = 0.3 × 0.7x = 0.21x,

n(B∩C') = 40% of n(B) = 0.4 × 0.1x = 0.04x,

n(B∩S) = 30% of n(B) = 0.3 × 0.1x = 0.03x,

n(B∩R) = 30% of n(B) = 0.3 × 0.1x = 0.03x,

n(C∩C') = 60% of n(C) = 0.6 × 0.2x = 0.12x,

n(C∩S) = 15% of n(C) = 0.15 × 0.2x = 0.03x,

n(C∩R) = 25% of n(C) = 0.25 × 0.2x = 0.05x,

n(C') = n(A∩C')  + n(B∩C')  + n(C∩C')  = 0.35x + 0.04x + 0.12x = 0.51x

n(S) = n(A∩S) + n(B∩S) + n(C∩S) = 0.14x + 0.03x + 0.03x = 0.20x

a. The probability that it will receive an A rating, if a new municipal bond is to be issued by a city,

P(\frac{A}{C'})=\frac{P(A\cap C')}{P(C')}=\frac{0.35x/x}{0.51x/x}=\frac{0.35}{0.51}=\frac{35}{51}

b. The proportion of municipal bonds are issued by cities = \frac{n(C')}{x}

=\frac{0.51x}{x}

=\frac{51}{100}

c. The proportion of municipal bonds are issued by suburbs = \frac{n(S)}{x}

=\frac{0.20x}{x}

=\frac{20}{100}

=\frac{1}{5}

3 0
3 years ago
Find the slope between:<br> (1,-2)<br> (2,-2)
stiks02 [169]

Answer: the slope would be 0

Step-by-step explanation:

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