First, note that 100 m = 0.100 km.
Recall that
<em>v</em>² - <em>u</em>² = 2 <em>a</em> ∆<em>x</em>
where <em>u</em> and <em>v</em> are initial and final velocities; <em>a</em> is acceleration; and ∆<em>x</em> is displacement. Solve for <em>a</em> :
(72 km/h)² - (108 km/h)² = 2 <em>a</em> (0.100 km)
<em>a</em> = ((72 km/h)² - (108 km/h)²) / (0.200 km)
<em>a</em> = -32,400 km/h²
If you want to convert this to m/s², we have
(-32,400 km/h²) = (-32,400 km/h²) (1000 m/km) (1/3600 h/s)²
(-32,400 km/h²) = -2.50 m/s²
<h3>
Answer:</h3>
-8/3 ft/s
<h3>
Step-by-step explanation:</h3>
<u>We are given:</u>
distance of the top of the ladder from the ground (h) = 12 ft
height of the ladder = 20 ft
rate of change of the distance of the base of ladder from the wall (dx/dt):
2 ft/s
<u>Finding the distance of the base of the ladder from the wall:</u>
From the Pythagoras's Theorem, we know that:
hypotenuse² = height² + base²
<em>replacing the given values</em>
20² = 12² + x²
400 = 144 + x²
x² = 256 [subtracting 144 from both sides]
x = 16 ft [taking the square root of both sides]
<u>The rate of change of the height of the Ladder from the ground:</u>
We know that:
h = 12 ft
(
) = ?
x = 16 ft
(
) = 2 ft/s
According to the Pythagoras's Theorem:
20² = x² + h²
<em>differentiating both sides with respect to time</em>




<em>replacing the variables</em>


[subtracting 64 from both sides]
[dividing both sides by 32]

Hence, the ladder will slide down at a speed of 8/3 feet per second
A one to one function is a function which matches <em>exactly one </em>x value with <em>exactly one </em>y value. The fancy term for this is an <em>injective function</em>.
Answer:
Plot each graph on the same coordinate system.
f(x)=−2
(2)x+4
Step-by-step explanation:
Step-by-step explanation:
in step 2 leon made mistake