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2 years ago

45000s is how many hours?

Mathematics

1 answer:

Vesnalui [34]2 years ago

3 0

1 s = 1/3600 hours

45000 s = 45000/3600

45000 s = 12.5 hours

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A factory dumps an average of 2.43 tons of pollutants into a river every week. if the standard deviation is 0.88 tons, what is t

vovikov84 [41]

25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%

5 0

2 years ago

What's the answer ?<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B255%20-%2030%7D%20" id="TexFormula1" title=" \sqrt{255

Aloiza [94]

Answer:

$\sqrt 255-30$

= -14.0312805773

7 0

2 years ago

Read 2 more answers

Do the following points represent a function? (0,2) (1,4) (0,4) (3,9) (5,8)

photoshop1234 [79]

<h3>Answer: No, this isn't a function.</h3>

Why not? Focus on the two points (0,2) and (0,4)

We have the x value x = 0 show up twice. Any time x repeats itself like this, it leads to "not a function" as the result.

In other words, the input x = 0 leads to multiple outputs y = 2 and y = 4 at the same time. A function is only possible if every x input leads to exactly one y output.

If you are a visual learner, then plot all of the points on the same xy grid. Then notice how (0,2) and (0,4) fail the vertical line test to show we don't have a function.

Side note: The y values can repeat themselves in a function.

8 0

1 year ago

How to find the multiplicity of a zero of a polynomial function?

Monica [59]

<span>The multiplicity of a zero of a polynomial function is how many times a particular number is a zero for a given polynomial.

For example, in the polynomial function $f(x)=x(x+4)^2(x-2)^3$ , the zeros are 0 with a multiplicity of 1, -4 with a multiplicity of 2, and 2 with a multiplicity of 3.

Although this polynomial has only three zeros, we say that it has six zeros (or degree of 6) counting the <span>multiplicities.</span></span>

3 0

3 years ago

Consider the rational expression (IMAGE ATTACHED)

Keith_Richards [23]

Answer:

3x² is a term in the numerator
x + 1 is a common factor
The denominator has 3 terms

Step-by-step explanation:

You can identify terms and count them before you start factoring. Doing so will identify 3x² as a term in the numerator, and will show you there are 3 terms in the denominator.

When you factor the expression, you get ...

$\dfrac{3x^2-3}{3x^2+2x-1}=\dfrac{3(x^2-1)}{(3x-1)(x+1)}=\dfrac{3(x-1)(x+1)}{(3x-1)(x+1)}$

This reveals a common factor of x+1.

So, the above three observations are true of this rational expression.

3 0

3 years ago