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3 years ago

What is the slope of the line passing through the points (6, 7) and (1, 5) ?

2 answers:

8 0

Well Slope is change in y over change in x. So y2-y1/x2-x1. 5-7=-2, 1-6=-5 so -2/-5 or 2/5 as negatives cancel each other out. A common way it is also represented is delta y/ delta x. Delta meaning change in. The answer is 2/5

Lyrx [107]3 years ago

4 0

5-7 = -2 and 1-6= -5 so the slope would be 2/5. you would set it up like this:

y=2/5x and then your y-intercept

You might be interested in

Find a common denominator for the pair of fractions. Then, write equivalent fractions with the common denominator.

DerKrebs [107]

4/12? It may be wrong, not sure

3 0

2 years ago

Raychel drove to the mountains last week there was heavy traffic on the way there and on the trip took 12 hours when Raychel dro

nevsk [136]

Suppose that this person drives at r mph going to the mountains, and gets there in 12 hours. Returning, this person drives at (r+20) mph and gets home in 8 hours. We don't know the distance yet, but can solve for the initial speed, r, by setting

d = 12r = (r+20)(8). Solving for r, r=40 mph (going) and (40+20)mph = 60 mph (returning. Since d=12 r, d = (12 hrs)(40 mph) = 480 miles (answer).

4 0

3 years ago

Solve for x. Please look at the picture and answer it. Thank you.

Tatiana [17]

<h3>Answer :- </h3>

x = 24

<h3>Solution :- </h3>

2x + 42 = 90
2x = 90 - 42
2x = 48
x = 48/2
x = 24

<em>Hope</em><em> it</em><em> helps</em><em> </em><em>~</em>

7 0

2 years ago

Read 2 more answers

Try this hard Math Problem if you dare!!

Dennis_Churaev [7]

Answer:

a. $(x - 3)^2 + 16$

b. $8(x -7)^2$

c. $(a^2 - 1)(7x - 6)$ or $(a+1)(a-1)(7x-6)$

d. $(x^2-4)(x^2+3)$ or $(x-2)(x+2)(x^2+3)$

e. $(a^n+b^n)(a^n-b^n)(a^{2n} +b^{2n})$

Step-by-step explanation:

$a.\ (x + 1)^2 - 8(x - 1) + 16$

Expand

$(x + 1)(x + 1) - 8(x - 1) + 16$

Open brackets

$x^2 + x + x + 1 - 8x + 8 + 16$

$x^2 + 2x + 1 - 8x + 24$

Collect Like Terms

$x^2 + 2x - 8x+ 1 + 24$

$x^2 - 6x+ 25$

Express 25 as 9 + 16

$x^2 - 6x+ 9 + 16$

Factorize:

$x^2 - 3x - 3x + 9 + 16$

$x(x -3)-3(x - 3) + 16$

$(x - 3)(x - 3) + 16$

$(x - 3)^2 + 16$

$b.\ 8(x - 3)^2 - 64(x-3) + 128$

Expand

$8(x - 3)(x - 3) - 64(x-3) + 128$

$8(x^2 - 6x+ 9) - 64(x-3) + 128$

Open Brackets

$8x^2 - 48x+ 72 - 64x+192 + 128$

Collect Like Terms

$8x^2 - 48x - 64x+192 + 128+ 72$

$8x^2 -112x+392$

Factorize

$8(x^2 -14x+49)$

Expand the expression in bracket

$8(x^2 -7x-7x+49)$

Factorize:

$8(x(x -7)-7(x-7))$

$8((x -7)(x-7))$

$8(x -7)^2$

$c.\ 7a^2x - 6a^2 - 7x + 6$

Factorize

$a^2(7x - 6) -1( 7x - 6)$

$(a^2 - 1)(7x - 6)$

The answer can be in this form of further expanded as follows:

$(a^2 - 1^2)(7x - 6)$

Apply difference of two squares

$(a+1)(a-1)(7x-6)$

$d.\ x^4 - x^2 - 12$

Express $x^4$ as $x^2$

$(x^2)^2 - x^2 - 12$

Expand

$(x^2)^2 +3x^2- 4x^2 - 12$

$x^2(x^2+3) -4(x^2+3)$

$(x^2-4)(x^2+3)$

The answer can be in this form of further expanded as follows:

$(x^2-2^2)(x^2+3)$

Apply difference of two squares

$(x-2)(x+2)(x^2+3)$

$e.\ a^{4n} -b^{4n}$

Represent as squares

$(a^{2n})^2 -(b^{2n})^2$

Apply difference of two squares

$(a^{2n} -b^{2n})(a^{2n} +b^{2n})$

Represent as squares

$((a^{n})^2 -(b^{n})^2)(a^{2n} +b^{2n})$

Apply difference of two squares

$(a^n+b^n)(a^n-b^n)(a^{2n} +b^{2n})$

6 0

3 years ago

10. Suppose y varies directly as x, and y = 9 when x = 3/2. Find y when x = 1

pogonyaev

Answer:

y = 6

Step-by-step explanation:

We need to interpret the question

y varies directly as x

y varies x

To equate it, we need to add a constant K

y = K/x

Using the information we are provided with

y = 9

x = 3/2

insert into

y = Kx

9 = K * 3/2

9 = 3K/ 2

3K = 9 *2

3k = 18

To get K, divide through by 3

3K/3 = 18/3

K = 6

Since we've gotten our K = 6

y = Kx

Using the new information

y = ?

x = 1

K = 6

y = 6* 1

y = 6

The new y = 6 , x =1

6 0

3 years ago