The weights are within 2 standard deviations of the mean are 8.9 lbs, 9.5 lbs and 10.4 lbs
<h3>How to determine the weights?</h3>
The given parameters are:
- Mean, μ = 9.5
- Standard deviation, σ = 0.5
The weights within 2 standard deviation is represented as:
μ - 2σ ≤ x ≤ μ + 2σ
Substitute known values
9.5 - 2(0.5) ≤ x ≤ 9.5 + 2(0.5)
Evaluate the product
9.5 - 1 ≤ x ≤ 9.5 + 1
Evaluate the sum
8.5 ≤ x ≤ 10.5
This means that the weights are between 8.5 and 10.5 (inclusive)
Hence, the weights are within 2 standard deviations of the mean are 8.9 lbs, 9.5 lbs and 10.4 lbs
Read more about standard deviation at:
brainly.com/question/11743583
The answer to the question asked is 5.
The least common multiple of 4 and 6 is 12. In the range 140 to 200, there are
... floor(200/12) - ceiling(140/12) + 1 = 16 - 12 + 1 = 5
integers divisible by 12.
_____
The list of answer choices suggests that the question is intended to be, "how many integers are divisible by 4 or 6?"
The number divisible by 4 is
... floor(200/4) - ceiling(140/4) + 1 = 50 - 35 + 1 = 16
The number divisible by 6 is
... floor(200/6) - ceiling(140/6) + 1 = 33 - 24 + 1 = 10
We know from the above that there are 5 values that are divisible by both 4 and 6, so will be counted twice if we simply add the above numbers. Hence the number of values divisible by 4 or 6 is
... 16 + 10 - 5 = 21 . . . . . corresponds to selection C)
Answer:
-2
Step-by-step explanation:
Distribute
2
(
3
+
4
)
+
2
=
4
+
3
{\color{#c92786}{2(3x+4)}}+2=4+3x
2(3x+4)+2=4+3x
6
+
8
+
2
=
4
+
3
{\color{#c92786}{6x+8}}+2=4+3x
6x+8+2=4+3x
2
Add the numbers
6
+
8
+
2
=
4
+
3
6x+{\color{#c92786}{8}}+{\color{#c92786}{2}}=4+3x
6x+8+2=4+3x
6
+
1
0
=
4
+
3
6x+{\color{#c92786}{10}}=4+3x
6x+10=4+3x
3
Rearrange terms
6
+
1
0
=
4
+
3
6x+10={\color{#c92786}{4+3x}}
6x+10=4+3x
6
+
1
0
=
3
+
4
6x+10={\color{#c92786}{3x+4}}
6x+10=3x+4
4
Subtract
1
0
10
10
from both sides of the equation
6
+
1
0
=
3
+
4
6x+10=3x+4
6x+10=3x+4
6
+
1
0
−
1
0
=
3
+
4
−
1
0
6x+10{\color{#c92786}{-10}}=3x+4{\color{#c92786}{-10}}
6x+10−10=3x+4−10
5
Simplify
Subtract the numbers
Subtract the numbers
6
=
3
−
6
6x=3x-6
6x=3x−6
6
Subtract
3
3x
3x
from both sides of the equation
6
=
3
−
6
6x=3x-6
6x=3x−6
6
−
3
=
3
−
6
−
3
6x{\color{#c92786}{-3x}}=3x-6{\color{#c92786}{-3x}}
6x−3x=3x−6−3x
7
Simplify
Combine like terms
Combine like terms
3
=
−
6
3x=-6
3x=−6
8
Divide both sides of the equation by the same term
3
=
−
6
3x=-6
3x=−6
3
3
=
−
6
3
\frac{3x}{{\color{#c92786}{3}}}=\frac{-6}{{\color{#c92786}{3}}}
33x=3−6
9
Simplify
Cancel terms that are in both the numerator and denominator
Divide the numbers
=
−
2
Answer:
c
Step-by-step explanation:
doesnt define a function