3c = 12.69
where c = # of greeting cars
Answer:
i would go for a but im not really sure. sorry if incorrect
Step-by-step explanation:
V=hpir^2
SA=2pir^2+2hpir
a.
SA=2pi9^2+2*36pi9
SA=2pi81+72pi9
SA=162pi+648pi
SA=810pi in^2
b.
aprox pi=3.14
810*3.14=2542.4cm^2
c.
V=36pi9^2
V=36pi81
V=2916pi in^3
d. 3.14=pi
2916*3.14=9156.24 in^3
The first term of this sequence is -20, and the common ratio is 11. Thus, the formula for the nth term is
a(n) = a(1)*(11)^(n-1), or (-20)*(11)^(n-1).
Thus, the 12th term is
a(12) = (-20)*(11)^(12-1) = -20(11)^11 = -20(2.85 times 10 to the 11th power.
or ... -5.71 times 10 to the 12th power.
