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Contact [7]
3 years ago
9

Given the function f(x)=(x+1)^2.what is the value of f(-2)

Mathematics
2 answers:
mojhsa [17]3 years ago
6 0

Answer: 1

<u>Explanation:</u>

f(x) = (x + 1)²

f(-2) is found by replacing "x" with "-2"

f(-2) = (-2 + 1)²

       = (-1)²

       = 1

ahrayia [7]3 years ago
3 0
F(x)= (x+1)^2

f(-2)= ((-2)+1)^2

= (-1)^2
= 1
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\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}

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