I just need someone to check my work and see if i did somethign wrong. Thanks.

Mathematics

1 answer:

Novosadov [1.4K]2 years ago

5 0

Your correct its right great job

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Find KL and show work

MissTica

Answer:

<u>Secant</u>: a straight line that intersects a circle at two points.

<u>Intersecting Secants Theorem</u>

If two secant segments are drawn to the circle from one exterior point, the product of the measures of one secant segment and its external part is equal to the product of the measures of the other secant segment and its external part.

From inspection of the given diagram:

M = Exterior point
MK = secant segment and ML is its external part
MS = secant segment and MN is its external part

Therefore:

⇒ ML · MK = MN · MS

Given:

MK = (x + 15) + 6 = x + 21
ML = 6
MS = 7 + 11 = 18
MN = 7

Substituting the given values into the formula and solving for x:

⇒ ML · MK = MN · MS

⇒ 6(x + 21) = 7 · 18

⇒ 6x + 126 = 126

⇒ 6x = 0

⇒ x = 0

Substituting the found value of x into the expression for KL:

⇒ KL = x + 15

⇒ KL = 0 + 15

⇒ KL = 15

6 0

1 year ago

Read 2 more answers

How many extraneous solutions does the equation below have? StartFraction 9 Over n squared 1 EndFraction = StartFraction n 3 Ove

BigorU [14]

The equation has one extraneous solution which is n ≈ 2.38450287.

Given that,

The equation;

$\dfrac{9}{n^2+1} =\dfrac{n+3}{4}$

We have to find,

How many extraneous solutions does the equation?

According to the question,

An extraneous solution is a solution value of the variable in the equations, that is found by solving the given equation algebraically but it is not a solution of the given equation.

To solve the equation cross multiplication process is applied following all the steps given below.

$\rm \dfrac{9}{n^2+1} =\dfrac{n+3}{4}\\\\9 (4) = (n+3) (n^2+1)\\\\36 = n(n^2+1) + 3 (n^2+1)\\\\36 = n^3+ n + 3n^2+3\\\\n^3+ n + 3n^2+3 - 36=0\\\\n^3+ 3n^2+n -33=0\\$