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Anit [1.1K]
3 years ago
13

The circle below is centered at the point (4,-3) and has a radius of length 3 what is it’s equation?

Mathematics
2 answers:
labwork [276]3 years ago
7 0
Hi there!

The standard form of the equation of a circle is:
(x - a) {}^{2} + (y - b) {}^{2} = r {}^{2}

With (a, b) representing the centre and r representing the radius of the circle.
Since the centre of the circle is (4, -3) and the radius is 3, we get the following equation:

(x - 4) {}^{2} + (y + 3) {}^{2} = 9
ivolga24 [154]3 years ago
3 0

Answer:

The correct answer is

(X+3)2 + (y-4)2 = 9

Step-by-step explanation:

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Answer:

B)g(x) - h(x) =  3x^3 - 5x^2 - 15x + 15

Step-by-step explanation:

Here, the given functions are:

g(x) = 5x^2- 10x + 9 \\h(x) = -3x^3+ 5x - 6

Now, g(x) - h(x) is : 

(5x^2- 10x + 9)  - ( -3x^3+ 5x - 6)\\= 5x^2- 10x + 9 + 3x^3 - 5x + 6\\= 3x ^3 + 5x ^2+  (-10 x - 5 x) + (9 + 6)\\= 3x^3 - 5x^2 - 15x + 15

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B) Hence, g(x) - h(x) =  3x^3 - 5x^2 - 15x + 15

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