Answer:
(a)= option 3
(b)= option 3
Step-by-step explanation:
(A) It is given that a sequence is defined by the recursive function
and ![a_{n}=a_{n-1}+n](https://tex.z-dn.net/?f=a_%7Bn%7D%3Da_%7Bn-1%7D%2Bn)
Now, substituting the value of n=2 in above equation,
![a_{2}=a_{1}+2](https://tex.z-dn.net/?f=a_%7B2%7D%3Da_%7B1%7D%2B2)
![a_{2}=1+2](https://tex.z-dn.net/?f=a_%7B2%7D%3D1%2B2)
![a_{2}=3](https://tex.z-dn.net/?f=a_%7B2%7D%3D3)
Again putting n=3,
![a_{3}=a_{2}+3](https://tex.z-dn.net/?f=a_%7B3%7D%3Da_%7B2%7D%2B3)
![a_{3}=3+3](https://tex.z-dn.net/?f=a_%7B3%7D%3D3%2B3)
![a_{2}=6](https://tex.z-dn.net/?f=a_%7B2%7D%3D6)
Putting n=4,
![a_{4}=a_{3}+4](https://tex.z-dn.net/?f=a_%7B4%7D%3Da_%7B3%7D%2B4)
![a_{4}=6+4](https://tex.z-dn.net/?f=a_%7B4%7D%3D6%2B4)
![a_{4}=10](https://tex.z-dn.net/?f=a_%7B4%7D%3D10)
Putting n=5,
![a_{5}=a_{4}+5](https://tex.z-dn.net/?f=a_%7B5%7D%3Da_%7B4%7D%2B5)
![a_{5}=10+5](https://tex.z-dn.net/?f=a_%7B5%7D%3D10%2B5)
![a_{5}=15](https://tex.z-dn.net/?f=a_%7B5%7D%3D15)
Putting n=6,
![a_{6}=a_{5}+6](https://tex.z-dn.net/?f=a_%7B6%7D%3Da_%7B5%7D%2B6)
![a_{6}=15+6](https://tex.z-dn.net/?f=a_%7B6%7D%3D15%2B6)
![a_{6}=21](https://tex.z-dn.net/?f=a_%7B6%7D%3D21)
Putting n=7,
![a_{7}=a_{6}+7](https://tex.z-dn.net/?f=a_%7B7%7D%3Da_%7B6%7D%2B7)
![a_{7}=21+7](https://tex.z-dn.net/?f=a_%7B7%7D%3D21%2B7)
![a_{7}=28](https://tex.z-dn.net/?f=a_%7B7%7D%3D28)
Hence, option 3 is correct.
(B) The given sequence is :
5, -10, 20, -40, 80.....
Since, the given sequence is GP, therefore
and r=-2
The nth term is given by:
![a_{n}=a_{1}r^{n-1}](https://tex.z-dn.net/?f=a_%7Bn%7D%3Da_%7B1%7Dr%5E%7Bn-1%7D)
For fifteenth term, put n=15 in above equation, we get
![a_{15}=5(-2)^{14}](https://tex.z-dn.net/?f=a_%7B15%7D%3D5%28-2%29%5E%7B14%7D)
=![5{\times}16384](https://tex.z-dn.net/?f=5%7B%5Ctimes%7D16384)
=![81920](https://tex.z-dn.net/?f=81920)
Hence, the fifteenth term is 81920.
Option 3 is correct.
Answer:
Step-by-step explanation:
Volume is found by length multiplied by width multiplied by height. Therefore our first equation is 2 multiplied by 5 and 1/3 or 16/5 as a mixed number multiplied by 10 3/4 or 43/10 as a mixed number. This will give us the total volume. As there are 8 servings, we will need to divide by 8 or multiply by 1/8 to find the volume of each serving. The final answer is 86/25 which simplified to 3 and 11/25
2.5 years required for an investment of 5000 dollars to grow to 6000 dollars at an interest rate of 7.5 percent per year, compounded quarterly.
Step-by-step explanation:
The given is,
Initial investment - $5000
Future amount - $6000
Interest rate - 7.5% (compounded quarterly)
Step:1
Formula to calculate the Future amount with compound interest,
...................................(1)
Where, F - Future amount
P - Initial amount
r - Rate of interest
n - No. of compounding in a year
t - Time period
From given,
F = $6000
P = $5000
r = 7.5%
n = 4 (compounded quarterly)
Equation (1) becomes,
![6000=5000(1+\frac{0.075}{4} )^{(t)(4)}](https://tex.z-dn.net/?f=6000%3D5000%281%2B%5Cfrac%7B0.075%7D%7B4%7D%20%29%5E%7B%28t%29%284%29%7D)
![\frac{6000}{5000} =(1+0.01875)^{4t}](https://tex.z-dn.net/?f=%5Cfrac%7B6000%7D%7B5000%7D%20%3D%281%2B0.01875%29%5E%7B4t%7D)
![1.2 = (1.01875)^{4t}](https://tex.z-dn.net/?f=1.2%20%3D%20%281.01875%29%5E%7B4t%7D)
Take log on both sides,
![log 1.2 = 4(t) log 1.01875](https://tex.z-dn.net/?f=log%201.2%20%3D%204%28t%29%20log%201.01875)
Substitute log values,
0.07918 = 4(t) (0.0080676)
= (t) (0.0322705)
= 2.45
t ≅ 2.5 years
Result:
2.5 years required for an investment of 5000 dollars to grow to 6000 dollars at an interest rate of 7.5 percent per year, compounded quarterly.
Answer:
A
Step-by-step explanation:
We have the equation:
![x^2+xy-3y=3](https://tex.z-dn.net/?f=x%5E2%2Bxy-3y%3D3)
Take the derivative of both sides with respect to x:
![\frac{d}{dx}[x^2+xy-3y]=\frac{d}{dx}[3]](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%5Bx%5E2%2Bxy-3y%5D%3D%5Cfrac%7Bd%7D%7Bdx%7D%5B3%5D)
Implicitly differentiate:
![2x+y+x\frac{dy}{dx}-3\frac{dy}{dx}=0](https://tex.z-dn.net/?f=2x%2By%2Bx%5Cfrac%7Bdy%7D%7Bdx%7D-3%5Cfrac%7Bdy%7D%7Bdx%7D%3D0)
Solve for dy/dx:
![\frac{dy}{dx}(x-3)=-2x-y\\](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%28x-3%29%3D-2x-y%5C%5C)
Divide:
![\frac{dy}{dx}=-\frac{2x+y}{x-3}](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%3D-%5Cfrac%7B2x%2By%7D%7Bx-3%7D)
To find dy/dx at (2, 1), substitute 2 for x and 1 for y. So:
![\frac{dy}{dx}_{(2, 1)}=-\frac{2(2)+1}{2-3}=-\frac{5}{-1}=5](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D_%7B%282%2C%201%29%7D%3D-%5Cfrac%7B2%282%29%2B1%7D%7B2-3%7D%3D-%5Cfrac%7B5%7D%7B-1%7D%3D5)
Hence, our answer is A.
Answer:
As given, measure of angle 4 is 70°
Then what would be the measure of ∠8.
Following cases comes into consideration
1. If ∠4 and ∠8 are supplementary angles i.e lie on same side of Transversal, then
∠4 + ∠8=180°
⇒70°+∠8=180° [∠4=70°]
⇒∠8=180°-70°
⇒∠8=110°
<u>2nd possibility</u>
But if these two angles i.e ∠4 and ∠8 forms a linear pair.Then
⇒ ∠4 + ∠8=180°
⇒70°+∠8=180° [∠4=70°]
⇒∠8=180°-70°
⇒∠8=110°
<u>3rd possibility</u>
If ∠4 and ∠8 are alternate exterior angles.
then, ∠4 = ∠8=70°
<u>4th possibility</u>
If If ∠4 and ∠8 are corresponding angles.
then, ∠4 = ∠8=70°
Out of four options given Option A[ 110° because ∠4 and ∠8 are supplementary angles], Option B[70° because ∠4 and ∠8 are alternate exterior angles.] and Option D[70° because ∠4 and ∠8 are corresponding angles.] are Correct.