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3 years ago

Who was the first to suggest the geocentric model?

Geography

2 answers:

Lynna [10]3 years ago

5 0

Answer:

The most highly developed geocentric model was that of Ptolemy of Alexandria (2nd century).

mariarad [96]3 years ago

5 0

Answer:

The most highly developed geocentric model was that of Ptolemy of Alexandria (2nd century).

Explanation:

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What is the most viscious type of magma

tiny-mole [99]

Answer:

Phreatomagmatic

Explanation:

These eruptions are produced when magma comes in contact with shallow groundwater causing the groundwater to flash to steam and be ejected along with pre-existing fragments of the rock and tephra from the magma.

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3 years ago

Which of the following city needs is a factor in determining the carrying capacity of a city's environment?

Kobotan [32]

A factor in determining the carrying capacity of a city's environment is the water resources available to meet city needs. This is assuming this is one of the following city needs in this question. This is the only answer that pertains to the environment.
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8 0

3 years ago

Many factories in northern Italy use _____ for energy.

Likurg_2 [28]

Answer: Hydroelectricity.

Explanation:

6 0

3 years ago

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What does the word minerals mean to you?

melamori03 [73]

The word minerals mean A formal definition of a mineral, as used by geologists would be: A naturally occurring inorganic solid that has a definite chemical composition, and an ordered internal structure. Geologists are able to identify minerals because they have characteristic physical properties.

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3 years ago

On a coordinate plane, a line goes through (negative 3, negative 3) and (negative 1, 5). What is the equation of the line parall

DENIUS [597]

Answer:

y=4x-16

Explanation:

The general form of the equation of a line is: y=mx+x, where m is the gradient and c is the y-intercept.

Given points (-3,-3) and (-1,5)

We are to find the equation of the line parallel to the given line with an x-intercept of 4.

First, we determine the value of the gradient of the line.

Gradient,

$m=\frac{y_2-y_1}{x_2-x_1} \\=\frac{5-(-3)}{-1-(-3)} \\=\frac{5+3}{-1+3}\\=\frac{8}{2}\\m=4$

Two lines are parallel if their gradients $m_1 \: and \: m_2$ are equal.

The gradient of the line parallel to the given line $m_2=4$

Since the x-intercept of the new line is 4, a point on the new line, $(x_1,y_1)=(4,0)$

Substituting $(x_1,y_1)=(4,0)$ into the equation of a line: , $y-y_1=m(x-x_1),$ we have:

$y-0=4(x-4)\\$Therefore:\\y=4x-16$

Therefore, the equation of the line is: y=4x-16

6 0

3 years ago

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