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3 years ago

what is the value of x in the diagram below? if necessary round your answer to the nearest tenth of a until

Mathematics

2 answers:

VladimirAG [237]3 years ago

6 0

Answer:

Step-by-step explanation:

Calculate AC using Pythagoras' identity in ΔABC

AC² = 20² - 12² = 400 - 144 = 256, hence

AC = $\sqrt{256}$ = 16

Now find AD² from ΔACD and ΔABD

ΔACD → AD² = 16² - (20 - x)² = 256 - 400 + 40x - x²

ΔABD → AD² = 12² - x² = 144 - x²

Equate both equations for AD², hence

256 - 400 + 40x - x² = 144 - x²

-144 + 40x - x² = 144 - x² ( add x² to both sides )

- 144 + 40x = 144 ( add 144 to both sides )

40x = 288 ( divide both sides by 40 )

x = 7.2 → C

Gnom [1K]3 years ago

5 0

Answer: the other answer for apex for the pre test is 6.5

Step-by-step explanation:

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Find the area to the nearest square foot of the shaded region below, consisting of a square with a circle cut out of it. Use 3.1

NeTakaya

Answer:

22 square feet

Step-by-step explanation:

Area of shaded region = Area of square - Area of circle. The diameter of the circle is also the length of the side of the square as the circumference of the circle is on the circumference of the square.

Area of circle = 3.14 × r × r

r = 10 ÷ 2

= 5

Area of circle = 3.14 × 5 × 5

= 78.5

Area of square = length × length

Area of square = 10 × 10

= 100

Area of shaded region = Square - Circle

= 100 - 78.5

= 21.5

= 22 (to the nearest square foot)

I hope this helps :)

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3 years ago

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3 years ago

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vivado [14]

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2 years ago

What is the lowest common denominator of 4,5,6,7,8 and 9?

Readme [11.4K]

Answer:

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Step-by-step explanation:

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4 years ago

Read 2 more answers

Dividing rational expressions

Galina-37 [17]

$\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-----------------------------\\\\
\cfrac{x+3}{x^2-2x}\cdot \cfrac{(x-2)^2}{x^2-9}\implies \cfrac{x+3}{x^2-2x}\cdot \cfrac{(x-2)(x-2)}{x^2-3^2}
\\\\\\
\cfrac{x+3}{x(x-2)}\cdot \cfrac{(x-2)(x-2)}{x^2-3^2}\implies \cfrac{\underline{x+3}}{x\underline{(x-2)}}\cdot \cfrac{\underline{(x-2)}(x-2)}{(x-3)\underline{(x+3)}}
\\\\\\
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3 years ago