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dsp73
4 years ago
13

Write a number that is the same when rounded to the nearest hundred and ten

Mathematics
1 answer:
aivan3 [116]4 years ago
4 0
The number one hundred and ten when rounded to the nearest one hundred and ten is the same number
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A standard deck of cards is made up of four suits: diamonds, spades, hearts, and clubs. What is the probability that you draw a
Oksi-84 [34.3K]

Answer:

1/2, because there's 4 suits, and so the probability of choosing 2 is 1/2.

Step-by-step explanation:

3 0
3 years ago
Help please this is khan academy
IRISSAK [1]

Answer:

9800 cm^2

Step-by-step explanation:

The area of a square is just the length of one of the sides squared. In the first image it's given that one of the sides is 70 cm and the shape is also a square pyramid so the base is going to be a square. So the area the base is (70 cm) ^ 2 = 4,900 cm^2. The area of a triangle is 1/2 bh. The base is given in the first image which is 70 cm and the height is also given which is 140 cm. This gives you the equation 0.5 * 140 cm * 70 cm = 4900 cm^2. Adding these two values gives you 9800 cm^2

6 0
2 years ago
Use the given values of n and p to find the minimum usual value μ - 2σ and the maximum usual value μ + 2σ. Round your answer to
fenix001 [56]

Given Information:  

number of trials = n = 1042

Probability of success = p = 0.80

Required Information:  

Maximum usual value = μ + 2σ = ?

Minimum usual value = μ - 2σ = ?

Answer:

Maximum usual value = 859.51

Minimum usual value = 807.78

Step-by-step explanation:

In a binomial distribution, the mean μ is given by

μ = np

μ = 1042*0.80

μ = 833.6

The standard deviation is given by

σ = √np(1 - p)

σ = √1042*0.80(1 - 0.80)

σ = √833.6(0.20)

σ = 12.91

The Maximum and Minimum usual values are

μ + 2σ = 833.6 + 2*12.91

μ + 2σ = 833.6 + 25.82

μ + 2σ = 859.51

μ - 2σ = 833.6 - 25.82

μ - 2σ = 807.78

Therefore, the minimum usual value is 807.78 and maximum usual value is 859.51

8 0
4 years ago
What is the ratio of the width to length of a folded sheet of paper if the rectangle formed when the sheet is folded in half is
Leno4ka [110]
Would it be 2:1? I really don't know, I haven't learned that yet, sorry
7 0
3 years ago
Read 2 more answers
Let the universal set, s, have 66 elements. a and b are subsets of s. set a contains 19 elements and set b contains 34 elements.
Otrada [13]

The cardinality of the union between two sets is given by

N(A\cup B) = N(A) + N(B) - N(A \cap B)

In fact, if an element is in both A and B, it is counted in both N(A) and N(B), so we're counting it twice. By subtracting the cardinality of the interserction, we're taking back one of these "extra-counted" element, and the count is correct. In your case, the numbers are

N(A \cup B) = 19+34-10 = 43

This means that the two sets cover, without repetitions, 43 of the 66 elements in the sets. So, there are

66-43 = 23

elements which are in neither A nor B

5 0
3 years ago
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