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alekssr [168]
3 years ago
6

If f(x)=2x−1, show that f(f(x))=4x−3. Find f(f(f(x))).

Mathematics
1 answer:
dybincka [34]3 years ago
6 0

Answer: f(f(f(x)))=8x-7

Step-by-step explanation:

Since we were given f(x) and f(f(x)), We plug that into f(x) again to get f(f(f(x))).

2(4x-3)-1                          [distribute]

8x-6-1                              [combine like terms]

8x-7

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The sum of two numbers is 75. The second number is 3 less than twice the first
Mandarinka [93]

Answer:

\large{\textbf{The two numbers are: 26 and 49}.\\}

Step-by-step explanation:

\large{\textup{assume the two numbers are $x$ and $y$.}}\\\large{\textup{The given sentences are written in mathematical terms as follows:}\\$$ x + y =  75  \hspace{25mm} (1)$$ $$ y = 2x - 3 \hspace{25mm} (2) $$  \\\textup{Substituting $(2)$ in $(1)$,}\\\begin{align*} &  \implies x + 2x - 3 = 75  \\& \implies 3x = 78 \\& \implies x = 26\end{align*}\textup{Substituting $x$ in $(1), \hspace{5mm} y = 49$} }

7 0
3 years ago
Connecticut families were asked how much they spent weekly on groceries. Using the following data, construct and interpret a 95%
Amanda [17]

Answer:

The 95% confidence interval for the population mean amount spent on groceries by Connecticut families is ($73.20, $280.21).

Step-by-step explanation:

The data for the amount of money spent weekly on groceries is as follows:

S = {210, 23, 350, 112, 27, 175, 275, 50, 95, 450}

<em>n</em> = 10

Compute the sample mean and sample standard deviation:

\bar x =\frac{1}{n}\cdot\sum X=\frac{ 1767 }{ 10 }= 176.7

s= \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} }       = \sqrt{ \frac{ 188448.1 }{ 10 - 1} } \approx 144.702

It is assumed that the data come from a normal distribution.

Since the population standard deviation is not known, use a <em>t</em> confidence interval.

The critical value of <em>t</em> for 95% confidence level and degrees of freedom = n - 1 = 10 - 1 = 9 is:

t_{\alpha/2, (n-1)}=t_{0.05/2, (10-1)}=t_{0.025, 9}=2.262

*Use a <em>t</em>-table.

Compute the 95% confidence interval for the population mean amount spent on groceries by Connecticut families as follows:

CI=\bar x\pm t_{\alpha/2, (n-1)}\cdot\ \frac{s}{\sqrt{n}}

     =176.7\pm 2.262\cdot\ \frac{144.702}{\sqrt{10}}\\\\=176.7\pm 103.5064\\\\=(73.1936, 280.2064)\\\\\approx (73.20, 280.21)

Thus, the 95% confidence interval for the population mean amount spent on groceries by Connecticut families is ($73.20, $280.21).

7 0
3 years ago
Find the experimental probability of randomly selecting a marble that is either green or purple. Write your answer in simplest f
EastWind [94]
Green or purple = 10 prob(green or purple) = 10/30 = 1/3
3 0
3 years ago
The last question for my test help
alisha [4.7K]

3 2/6

5/6*4=20/6

20/6= 3 2/6 OR 3 1/3

8 0
3 years ago
Can Someone help me in this?
My name is Ann [436]

Answer:

You should ask your teacher for help and pay attention in class

Step-by-step explanation:

7 0
3 years ago
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