Convert the equation to the standard form for a hyperbola by completing the square on x and y. x2 - y2 + 6x - 4y + 4 = 0?

1 answer:

7 0

X² + 6x + ____ - (y² + 4y + ____ ) = -4 + ____ + ____
x² + 6x + 9 - (y² + 4y + 4 ) = -4 + 9 + -4
(x + 3)² - (y + 2)² = 1

Answer: B

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