Suzanne owns stock worth $2,400. She owes $5,200 in student loans, and $2,500 on a credit car. She owes $1,800 on a car that is
1 answer:
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Given that <span>For
a certain model of car the distance 
required to stop the vehicle if
it is traveling at 
mi/h is given by the formula ![d=v+\frac{v^2}{20}, where [tex]d](https://tex.z-dn.net/?f=d%3Dv%2B%5Cfrac%7Bv%5E2%7D%7B20%7D%2C%20where%20%5Btex%5Dd%20)
is measured in feet.
If Kerry wants her stopping distance not to exceed 75 ft, then the range of speeds (in mi/h) can she travel is obtained as follows:
Therefore, the range of speed she can travel is
</span>
If Kerry wants her stopping distance not to exceed 75 ft, then the range of speeds (in mi/h) can she travel is obtained as follows:
Therefore, the range of speed she can travel is
</span>
Answer:
no solutions
Step-by-step explanation:
Hi there!
We're given this system of equations:
x+y=3
4y=-4x-4
and we need to solve it (find the point where the lines intersect, as these are linear equations)
let's solve this system by substitution, where we will set one variable equal to an expression containing the other variable, substitute that expression to solve for the variable the expression contains, and then use the value of the solved variable to find the value of the first variable
we'll use the second equation (4y=-4x-4), as there is already only one variable on one side of the equation. Every number is multiplied by 4, so we'll divide both sides by 4
y=-x-1
now we have y set as an expression containing x
substitute -x-1 as y in x+y=3 to solve for x
x+-x-1=3
combine like terms
-1=3
This statement is untrue, meaning that the lines x+y=3 and 4y=-4x-4 won't intersect.
Therefore the answer is no solutions
Hope this helps! :)
The graph below shows the two equations graphed; they are parallel, which means they will never intersect. If they don't intersect, there's no common solution
