Answer:
x = 0
Step-by-step explanation:
To 'solve' means to find the x values that make the equation equal zero, so
0 = (3x)/[(x + 5)(x - 4)
Multiply both sides by the denominator to get rid of the fraction
0[(x + 5)(x - 4)] = [(3x)(x + 5)(x - 4)]/[(x + 5)(x - 4)]
0 = 3x
0 = x (divide both sides by 3)
So x = 0 is the solution for this equation
Step-by-step explanation:
<u>y</u> - <u>1</u> = <u>-</u><u>3</u>
x - 0 2
2y - 2 = -3x
2y = -3x + 2
Area of rectangle = 2(2w - 5) is the factored form of given expression
Multiplying the length and width of a rectangle, we get the area of the rectangle
<em><u>Solution:</u></em>
Given that, area of rectangle is 4w - 10 square units
We have to factor the expression
From given,
Area of rectangle = 4w - 10
Take 2 as common factor
Area of rectangle = 2(2w - 5)
Thus the given expression is factored
<em><u>The area of rectangle is given as:</u></em>


Thus, multiplying the length and width of a rectangle, we get the area of the rectangle
When we multiply 2 with 2w - 5 we get the area of rectangle
From above we can say,
Length = 2 or 2w - 5
Width = 2w - 5 or 2
So when dimensions of rectangle are multiplied we get area of rectangle
First, you must know these formula d(e^f(x) = f'(x)e^x dx, e^a+b=e^a.e^b, and d(sinx) = cosxdx, secx = 1/ cosx
(secx)dy/dx=e^(y+sinx), implies <span>dy/dx=cosx .e^(y+sinx), and then
</span>dy=cosx .e^(y+sinx).dx, integdy=integ(cosx .e^(y+sinx).dx, equivalent of
integdy=integ(cosx .e^y.e^sinx)dx, integdy=e^y.integ.(cosx e^sinx)dx, but we know that d(e^sinx) =cosx e^sinx dx,
so integ.d(e^sinx) =integ.cosx e^sinx dx,
and e^sinx + C=integ.cosx e^sinxdx
finally, integdy=e^y.integ.(cosx e^sinx)dx=e^2. (e^sinx) +C
the answer is
y = e^2. (e^sinx) +C, you can check this answer to calculate dy/dx