we know that
The measure of the external angle is the semidifference of the arcs that it covers
so
∠MLN=(1/2)*(mayor arc MN-minor arc MN)
Let
x------> minor arc MN
major arc MN=360-x
substitute in the formula above
∠MLN=(1/2)*(mayor arc MN-minor arc MN)
75.86=(1/2)*(360-x-x)------> 151.72=(360-2x)------>360-151.72=2x
x=104.14°
therefore
the answer is
the measure of arc MN (minor arc) is 104.14°
Answer:
f(6) = 2
Step-by-step explanation:
Since y is a function of x, that is y = f(x), f(6) implies that we shall be evaluating the value of y when the value of x is 6.
To do this we shall draw a vertical line, x = 6 and check where this line intersects with the graph of the function f(x)
The vertical line x = 6 intersects with the graph of the function f(x) on the horizontal line y = 2. The function f(x) assumes the value 2 for values of x between 4 and 8. Therefore, f(6) = 2
Answer:
there was a 270% mistake i think
Step-by-step explanation:
Answer:
24 es la respuesta correct
Step-by-step explanation:
20% or 2 cm 1 dm = 10 cm.