Answer:
II. One and only one solution
Step-by-step explanation:
Determine all possibilities for the solution set of a system of 2 equations in 2 unknowns. I. No solutions whatsoever. II. One and only one solution. III. Many solutions.
Let assume the equation is given as;
x + 3y = 11 .... 1
x - y = -1 ....2
Using elimination method
Subtract equation 1 from 2
(x-x) + 3y-y = 11-(-1)
0+2y = 11+1
2y = 12
y = 12/2
y = 6
Substitute y = 6 into equation 2:
x-y = -1
x - 6 = -1
x = -1 + 6
x = 5
Hence the solution (x, y) is (5, 6)
<em>Hence we can say the equation has One and only one solution since we have just a value for x and y</em>
<em />
Inverse variation is of the form:
y=k/x, which we can express as:
yx=k we are given the point (2/3, 7) so we can solve for k
7(2/3)=k
14/3=k
y=14/(3x), so when x=7/3
y=(14/3)/(7/3)
y=(14/3)(3/7)
y=2
Answer:
Step-by-step explanation:
<u><em>The complete options are</em></u>
a) x - 2y = 30
b) 4x - 3y = 30
c) 3x - 4y = 30
d) 6x - 6y = 30
The given equation is
<u>Verify option d</u>
we have
Divide by 6 both sides
therefore
and are equivalent
178 * 18 + (98-2)
3204 + 96
3300
The maximum revenue is $700 which is at 16 combo A and 12 combo B.
<h3>
Inequality</h3>
An inequality is an expression that shows the non equal comparison of two or more numbers and variables.
Let x represent the number of combo A and y represent the number of combo B, hence:
10x + 20y ≤ 400 (1)
Also:
x + y ≤ 28 (2)
The solution is at (16,12). Hence:
Revenue = 21.25 * 16 + 30 * 12 = $700
The maximum revenue is $700 which is at 16 combo A and 12 combo B.
Find out more on Inequality at: brainly.com/question/24372553
