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Shkiper50 [21]
3 years ago
13

Suppose that six individuals are interested in taking part in a study relating BMI to a number of health outcomes. The following

6 numbers represent the individuals' BMI (kg/m2). a. 25.78 b. 21.06 c. 36.54 d. 29.51 e. 18.96 f. 34.05 A) What is the mean and median of the individuals' BMIs? B) Suppose that a BMI above 30 is considered obese. What is the relative frequency of obes in this group?
Mathematics
1 answer:
posledela3 years ago
5 0

Answer:

a) Mean = 27.65

Median = 27.645

b) Relative Frequency = 33.33%

Step-by-step explanation:

We are given the following data set:

25.78, 21.06, 36.54, 29.51, 18.96, 34.05

a) Mean and Median

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{165.9}{6} = 27.65

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

Sorted data: 18.96, 21.06, 25.78, 29.51, 34.05, 36.54

\text{Median} = \displaystyle\frac{25.78 +29.51}{2} = 27.645

b) BMI above 30 is considered obese

Frequency of obese in the given sample = 2

Relative Frequency =

\displaystyle\frac{\text{Frequency of obese}}{\text{Total number}} = \frac{2}{6} = 0.3333 = 33.33\%

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