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Shkiper50 [21]
2 years ago
13

Suppose that six individuals are interested in taking part in a study relating BMI to a number of health outcomes. The following

6 numbers represent the individuals' BMI (kg/m2). a. 25.78 b. 21.06 c. 36.54 d. 29.51 e. 18.96 f. 34.05 A) What is the mean and median of the individuals' BMIs? B) Suppose that a BMI above 30 is considered obese. What is the relative frequency of obes in this group?
Mathematics
1 answer:
posledela2 years ago
5 0

Answer:

a) Mean = 27.65

Median = 27.645

b) Relative Frequency = 33.33%

Step-by-step explanation:

We are given the following data set:

25.78, 21.06, 36.54, 29.51, 18.96, 34.05

a) Mean and Median

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{165.9}{6} = 27.65

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

Sorted data: 18.96, 21.06, 25.78, 29.51, 34.05, 36.54

\text{Median} = \displaystyle\frac{25.78 +29.51}{2} = 27.645

b) BMI above 30 is considered obese

Frequency of obese in the given sample = 2

Relative Frequency =

\displaystyle\frac{\text{Frequency of obese}}{\text{Total number}} = \frac{2}{6} = 0.3333 = 33.33\%

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Which statement(s) is (are) correct?
Anna71 [15]

Answer:

<em>statements 3 and 4 are correct.</em>

Step-by-step explanation:

(1)

The probability of choosing cured pasta and bear= probability that the card is king.

Hence, The probability of choosing cured pasta and bear=\dfrac{4}{52}=\dfrac{1}{13}

Probability of choosing baked cucumber and lime mutton=probability that the card is 3.

as there are 4 cards that are '3'.

Hence Probability of choosing baked cucumber and lime mutton=\dfrac{4}{52}=\dfrac{1}{13}

as both the probabilities are equal.

Hence statement 1 is incorrect.

(2)

The probability of choosing gooseberry & passion fruit cheesecake= Probability taht the card is ace.

as there are 4 cards which are ace out of 52 cards.

Hence, The probability of choosing gooseberry & passion fruit cheesecake=\dfrac{4}{52}=\dfrac{1}{13}

probability of choosing poached fennel & lemon alligator=Probability that the card is a face card.

As there are 12 face cards out of 52 cards.

Hence, probability of choosing poached fennel & lemon alligator=\dfrac{12}{52}=\dfrac{3}{13}

Hence, the probability of choosing gooseberry and passion fruit cheesecake is smaller than the probability of choosing poached fennel & lemon alligator.

Hence statement 2 is false.

(3)

The probability of choosing a praline wafer=probability that the card is a diamond.

as there are 13 diamond cards out of 52 cards.

The probability of choosing a praline wafer=\dfrac{13}{52}=\dfrac{1}{4}

the probability of choosing poached fennel & lemon alligator=Probability that the card is a face card.

As there are 12 face cards out of 52 cards.

Hence, probability of choosing poached fennel & lemon alligator=\dfrac{12}{52}=\dfrac{3}{13}

Hence, The probability of choosing a praline wafer is greater than the probability of choosing poached fennel & lemon alligator.

Hence statement 3 is correct.

(4)

The probability of choosing pressure-cooked mushroom & garlic chicken =probability that the card is red.

As there are 26 red cards out of 52 cards.

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probability of choosing an oven-baked apple & lavender calzone =probability that the card is black.

As there are 26 red cards out of 52 cards.

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Hence statement 4 is true.

(5)

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As there are 26 red cards out of 52 cards.

Hence,  

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the probability of choosing a praline wafer=probability that the card is a diamond.

as there are 13 diamond cards out of 52 cards.

The probability of choosing a praline wafer=\dfrac{13}{52}=\dfrac{1}{4}

Hence, the probability of choosing pressure-cooked mushroom & garlic chicken and the probability of choosing a praline wafer are not same.

Hence, statement 5 is not correct.


6 0
3 years ago
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lapo4ka [179]
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7 0
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Andru [333]

Answer:

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4 0
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