Answer:

Step-by-step explanation:
This half life exponential decay equation goes by the formula:

Where

Since half life is given as 22, we plug that into "Half-Life" in the formula for k and then plug in the formula for k into the exponential decay formula:
So,

Now

third choice is correct.
- Line<span> of </span>Best Fit<span>. A </span>line<span> of </span>best fit<span> (or "</span>trend<span>" </span>line<span>) is a straight </span>line<span> that </span>best<span> represents the data on a </span>scatter plot<span>. This </span>line<span> may pass through some of the points, none of the points, or all of the points.</span>
This is easy, all you need to do is divide 48/2.5 and you have your answer.
Answer:
around 3
Step-by-step explanation:
A solution to an equation is a number that can be plugged in for the variable to make a true number statement. Example 1: Substituting 2 for x in. 3x+5=11. gives.