Answer:
Your Answer is ...
x > 3 or x < -7
Step-by-step explanation:
1. x > 3 worked out
|X + 2| > 5
Solve absolute Value
|X + 2| > 5
We know either |X + 2| > 5 or x + 2 < - 5
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2. x < -7 Worked out
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Answer:
Step-by-step explanation:
<em>Given:</em>
Mn is diameter of circle having centre O
and BD = OD,
<em><u>To prove that:</u></em>
<u></u>
<em>Solution:</em>
Join the points O and B and draw OB,
On joining the line,
in ∆OCD and ∆OBD,
OC =OB → (Radius of same circle)
BD =CD → (from given)
OD =OD → (Common side in both the triangles)
Hence ∆OCD and ∆OBD are congruent from SSS property.
so we can say that,
Consider above prove as statement A
Corresponding angles of congruent traingle.
in ∆ OAB,
OA = OB (radius of same circle)
hence ∆OAB is an isosceles traingle.
We know that opposite angle of isosceles traingle are always equal. hence,
Consider above prove as statement B
From Statement A & B we can say that
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Answer: The true statement is,
'N is the mid point of JL'.
Step-by-step explanation:
Since, By the given diagram we get the following information,
M is mid point of KL because, KM=ML,
N is the mid point of JL Because, JN=NL
If we connect the points M and N then we get a line MN,
Which is called mid segment.
And, By the Mid point theorem,
and MN= KJ/2 = 12.8/2=6.4 m
Therefore from the above information we can say that only second Option is correct.