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kramer
3 years ago
11

In quadrilateral ABCD, diagonals AC and BD bisect one another: What statement is used to prove that quadrilateral ABCD is a para

llelogram?
A) Segment AP is congruent to segment CP.

B) Segment BP is congruent to segment AP

C) Sides AB and BC are congruent.

D) Triangles BCP and CDP are congruent.
Mathematics
2 answers:
juin [17]3 years ago
6 0
Statement B is true only for a square. Statements C and D are true only for a square and a rhombus but we want to prove that quadrilateral ABCD is a parallelogram.
Answer: A ) Segment AP is congruent to segment CP.
Llana [10]3 years ago
5 0

The <u>correct answer</u> is:


A) AP is congruent to CP.


Explanation:


The only information we are given is that the diagonals AC and BD bisect each other at some unknown point. This means that the distance from A to this point is the same as the distance from this point to C; this gives us AP congruent to CP.

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If a= b^2/3 and b= c^3/4; what is the relation between a and c?
Lorico [155]

Answer: a = c^(1/2) which is the first answer choice of the list

Work Shown:

a = b^(2/3) ... given equation

a = (c^(3/4))^(2/3) ... replace b with c^(3/4)

a = c^((3/4)*(2/3)) .... multiply exponents

a = c^(1/2) .... Simplify; note the 3's cancel, also 2/4 turns into 1/2

6 0
3 years ago
PLEASE ASAP GIVING BRAINLIEST
Elodia [21]

Answer:

29.7cm²

Step-by-step explanation:

The area of the shaded region = area of rectangle - area of circle

Area of rectangle:

A=lw

=7*5

=35cm²

Diameter of circle is 2.6cm. Radius is half diameter: 2.6/2=1.3cm

Area of circle:

A=πr²

=(3.14)(1.3²)

=5.3066cm²

35 - 5.3066 = 29.6934cm²

8 0
3 years ago
Read 2 more answers
) Mike bought nine new baseball trading cards to add to his collection. The next
marysya [2.9K]

Answer:

75

Step-by-step explanation:

75 divided by 2

7 0
4 years ago
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Given: Triangle ABC : triangle ADB. AB =24, AD =16 <br> Find: AC
RoseWind [281]

Answer:

<h2>AC = 36.01</h2>

Step-by-step explanation:

Given ΔABC and ΔADB, since both triangles are right angled triangles then the following are true.

From ΔADB, AB² = AD²+BD²

Given AB = 24 and AD = 16

BD² = AB² - AD²

BD² = 24²-16²

BD² = 576-256

BD² = 320

BD = \sqrt{320}

BD = 17.9

from ΔABC, AC² = AB²+BC²

SInce AC = AD+DC and BC² = BD² + DC² (from ΔBDC )we will have;

(AD+DC)² = AB²+ (BD² + DC²)

Given AD = 16, AB = 24 and BD = 17.9, on substituting

(16+DC)² = 24²+17.9²+ DC²

256+32DC+DC² =  24²+17.9²+ DC²

256+32DC = 24²+17.9²

32DC = 24²+17.9² - 256

32DC = 640.41

DC = \frac{640.41}{32}

DC = 20.01

Remember that AC = AD+DC

AC = 16+20.01

AC = 36.01

6 0
3 years ago
Solve for y: x=4y-3
77julia77 [94]

Answer:

y = (x+3)/4

Step-by-step explanation:

add 3 to both sides

so x + 3 = 4y-3+3

x + 3 = 4y

Divide both sides by 4

(x + 3)/4 = 4y/4

(x+3)/4 = y

3 0
3 years ago
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