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mixas84 [53]
3 years ago
9

Find the percent increase from 2005- 2010

Mathematics
1 answer:
ivanzaharov [21]3 years ago
3 0

Answer:

2.4 more.

Step-by-step explanation:

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1 is C <span>4 × 10^3 ft^3
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Margo can purchase tile at a store for $0.99 per tile and rent a tile saw for $18. At another store she can borrow the tile saw
Margarita [4]
(0.99x) + 18 = 1.19x

18 = 1.19x
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18/0.2 = x

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Which expression have the same value as the product of 2.7 and 4
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Step-by-step explanation:

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3 years ago
Whats the value of x
Elenna [48]

Answer:

x = 105°

Step-by-step explanation:

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3 years ago
A horticulturist working for a large plant nursery is conducting experiments on the growth rate of a new shrub. Based on previou
sergejj [24]

Answer:

t=\frac{2.9-3}{\frac{0.3}{\sqrt{50}}}=-2.357    

df=n-1=50-1=49  

p_v =P(t_{(49)}  

Since the p value is less than the significance level of 0.1 we have enough evidence to reject the null hypothesis and we can conclude that the true growth rate is significantly less than 3 cm per week

Step-by-step explanation:

Information given

\bar X=2.90 represent the sample mean for the growth

s=0.30 represent the sample standard deviation

n=50 sample size  

\mu_o =3 represent the value to check

\alpha=0.1 represent the significance level

t would represent the statistic

p_v represent the p value for the test

System of hypothesis

We want to verify if the true mean for the growth us less than 3cm per week, the system of hypothesis are:  

Null hypothesis:\mu \geq 3  

Alternative hypothesis:\mu < 3  

We don't know the population deviation so we can use the t statistic:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info given we got:

t=\frac{2.9-3}{\frac{0.3}{\sqrt{50}}}=-2.357    

The degrees of freedom are given by:

df=n-1=50-1=49  

The p value for this case would be given by:

p_v =P(t_{(49)}  

Since the p value is less than the significance level of 0.1 we have enough evidence to reject the null hypothesis and we can conclude that the true growth rate is significantly less than 3 cm per week

3 0
3 years ago
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