Explanation:
Experiment Initial [CS2] (mol/L) Initial Rate (mol/L·s)
1 0.100 2.7 × 10−7
2 0.080 2.2 × 10−7
3 0.055 1.5 × 10−7
4 0.044 1.2 × 10−7
a) Choose the rate law for the decomposition of CS2.
Comparing equations 1 and 3, reducing the initial concentration by almost half (from 0.100 to 0.055) leads too the rate of reaction to be reduced by almost half (from 2.7 × 10−7 to 1.5 × 10−7).
This signifies that the reaction is a first order reaction.
Rate = k [CS2]
(b) Calculate the average value of the rate constant.
Taking equation 1.
Rate = k [CS2]
k = Rate / [CS2]
k = 0.100 / (2.7 × 10−7) = 0.037 x 10^8 = 3.7 x 10^6s-1
In this reaction
ester is reduced to
aldehyde. Such reduction can not be achieved by reacting reducing agents like
LiAlH₄ because it will further reduce aldehydes to alcohols. So, in order to stop reduction at alddehyde, ester is reacted with bulky reducing agent, <span>
Diisobutylaluminium hydride (DIBAL) which works with same mechanism as that LiAlH</span>₄ do. It also add hydride to carbonyl group. The reaction is shown below,
Answer:process of using an electrical current to separate water into hydrogen and oxygen gas
Explanation:
Answer:
32
Step-by-step explanation:
There are two ways you can count the valence electrons.
A. From the Periodic Table
1 × P (Group 15) = 5
4 × O (Group 16) = 4 × 6 = 24
+3 e⁻ (for the charges) = <u> 3</u>
Total = 32
B. From the Lewis structure
In the <em>Lewis structure</em> (below), each line (bond) represents a pair of bonding electrons, and each dot represents an unbound electron (half a lone pair).
5 lines (bonds) = 5 × 2 = 10
3 single-bonded O atoms = 3 × 6 = 18
1 double-bonded O atom = <u> 4</u>
Total = 32
A. the removal of energy because you will be losing heat