What is the velocity of a skateboarder whose momentum is 100 kg-m/s and mass is 15 kg? Round to the nearest hundredth. A. 3.33 m
2 answers:
Answer : The correct option is, (D) 6.67 m/s
Explanation : Given,
Momentum = 100 Kg m/s
Mass = 15 Kg
Momentum : It is defined a the product of mass and the velocity of an object.
Formula used :
where,
p = momentum
m = mass
v = velocity
Now put all the given values in the above formula, we get the velocity of a skateboarder.
Therefore, the velocity of a skateboarder is, 6.67 m/s
You might be interested in
Potassium dichromate reacts with sulfuric acid to form chromic acid, H₂CrO₄ which is a very strong oxidizing agent. The secondary alcohol, (<em>R</em>)-2-butanol will be oxidized in the presence of chromic acid, but it can only be as oxidized as far as the ketone, which is the product shown, 2-butanone.
Sodium borohydride is a reducing agent that will reduce a ketone or aldehyde to an alcohol. When sodium borohydride reacts with 2-butanone, it reduces it to 2-butanol. However, the alcohol is no longer chiral as it was in the beginning since the sodium borohydride can add a hydride to either face of the carbonyl, which results in a racemic mixture of alcohols. This explains why the product has the same refractive index and boiling point as (<em /><em>R</em>)-2-butanol, however, the product formed would no longer be optically active.
Sodium borohydride is a reducing agent that will reduce a ketone or aldehyde to an alcohol. When sodium borohydride reacts with 2-butanone, it reduces it to 2-butanol. However, the alcohol is no longer chiral as it was in the beginning since the sodium borohydride can add a hydride to either face of the carbonyl, which results in a racemic mixture of alcohols. This explains why the product has the same refractive index and boiling point as (<em /><em>R</em>)-2-butanol, however, the product formed would no longer be optically active.