What is the velocity of a skateboarder whose momentum is 100 kg-m/s and mass is 15 kg? Round to the nearest hundredth. A. 3.33 m
2 answers:
Answer : The correct option is, (D) 6.67 m/s
Explanation : Given,
Momentum = 100 Kg m/s
Mass = 15 Kg
Momentum : It is defined a the product of mass and the velocity of an object.
Formula used :
where,
p = momentum
m = mass
v = velocity
Now put all the given values in the above formula, we get the velocity of a skateboarder.
Therefore, the velocity of a skateboarder is, 6.67 m/s
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Answer :
The mass of excess mass of ,
are, 1.908 g, 0 g, 12.144 g and 3.74 g respectively.
Explanation : Given,
Mass of = 4.25 g
Mass of = 7.50 g
Molar mass of = 106 g/mole
Molar mass of = 170 g/mole
Molar mass of = 276 g/mole
Molar mass of = 85 g/mole
First we have to calculate the moles of and
.
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 2 moles of react with 1 mole of
So, 0.044 moles of react with
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
The excess mole of = 0.040 - 0.022 = 0.018 mole
Now we have to calculate the mass of excess mole of .
Now we have to calculate the moles of .
As, 1 moles of react to give 1 moles of
So, 0.044 moles of react to give 0.044 moles of
Now we have to calculate the mass of .
Now we have to calculate the moles of .
As, 2 moles of react to give 2 moles of
So, 0.044 moles of react to give 0.044 moles of
Now we have to calculate the mass of .