Answer:
2 RootIndex 4 StartRoot 4 EndRoot
Step-by-step explanation:
we have
Decompose the number 64 in prime factors
substitute
![64^{\frac{1}{4}}=(2^{4}2^{2})^{\frac{1}{4}}=2^{\frac{4}{4}}2^{\frac{2}{4}}=2\sqrt[4]{4}](https://tex.z-dn.net/?f=64%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%3D%282%5E%7B4%7D2%5E%7B2%7D%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%3D2%5E%7B%5Cfrac%7B4%7D%7B4%7D%7D2%5E%7B%5Cfrac%7B2%7D%7B4%7D%7D%3D2%5Csqrt%5B4%5D%7B4%7D)
The least common multiple (LCM) can be determined by factoring out the terms first,
165xy = (3)(11)(5)(x)(y)
77x³y = (7)(11)(x)(x)(x)(y)
Copy the factors writing off the repeated factors only once,
LCM = (3)(11)(5)(x)(y)(7)(x)(x)= 1155x³y
The answer is 1155x³y (first choice)
Answer:
We have the equation A*C = A
Now, as both sides of the equality are the same thing, we can do the same operation to both sides and the equality will remain true.
We can divide both sides by A and get:
(A*C)/A = A/A
C = 1
So here we finded the value of A.
If A and C are matrices, then C is the identity matrix.
Answer:
8 + 90 + NaN + 4000 + 50000
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