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Novosadov [1.4K]
4 years ago
5

Find the area of quadrilateral ABCD.

Mathematics
2 answers:
maria [59]4 years ago
8 0
The correct answer is B. 14.89 units squared.

Find the area of each triangle and add them together. Heron’s formula explains it better than me. Lol
nalin [4]4 years ago
3 0

Answer:

<h2>            14.89 units²</h2>

Step-by-step explanation:

P_{ABCD}=P_{ACD}+P_{ABD}

We can use Heron's formula to calculate area of triangles:

P_\triangle=\sqrt{s(s-a)(s-b)(s-c)}   where:

a, b, c  - sides of triangle

s  - semi-perimetr of triangle  {(a+b+c):2}

ΔACD:

a = 4.39 ,   b = 3.42  ,  c = 4.57

s = (4.39 + 3.42 + 4.57)÷2 = 12.38÷2 = 6.19

P_{ACD}=\sqrt{6.19(6.19-4.39)(6.19-3.42)(6.19-4.57)}\\\\P_{ACD}=\sqrt{6.19\cdot1.8\cdot2.77\cdot1.62}=\sqrt{49.9986108}=7.070969579...\\\\P_{ACD}\approx7.071

ΔACD:

a = 5.44 ,   b = 7.84 ,   c = 3.42

s = (5.44 + 7.84 + 3.42)÷2 = 16.7÷2 = P_{ACD}=\sqrt{8.35(8.35-5.44)(8.35-7.84)(8.35-3.42)}\\\\P_{ACD}=\sqrt{8.35\cdot2.91\cdot0.51\cdot4,93}=\sqrt{61.09371855}=7.81624708...\\\\P_{ACD}\approx7.816

P_{ABCD}=P_{ACD}+P_{ABD}\\\\P_{ABCD}\approx7.071+7.816 = 14.887\\\\P_{ABCD}\approx 14.89

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Answer:

See attachment for graph

<em></em>

Step-by-step explanation:

Given

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Required

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<em>See attachment for graph</em>

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