Distance = speed x time
Distance travelled by car A when car B started = 60 x 2 = 120 miles
Number of miles remaining at the time car B started = 400 - 120 = 280 miles.
At time of their meeting both cars has travelled a combined distance of 280 miles and has spent the same time.
Let t be the time they travelled together before they meet, then the sum of the distance travelled by car A and car B is 280miles.
60t + 80t = 280
140t = 280
t = 280/140 = 2 hours
After 2 hours car A has travelled a further 60 x 2 = 120 miles and car B has travelled 80 x 2 = 160 miles.
Total distance travelled be car A is 120 + 120 = 240 miles
Midpoint of the journey = 400/2 = 200 miles
Therefre, at the time they met, the were 40 miles from the midpoint and they are close to San Francisco.
Answer:
what is the problem
Step-by-step explanation:
Answer:
x= −1/ 240
Step-by-step explanation:
hope this helps!!
Somewhere you're given the equation for height as a function of time:
... h(t) = -16t² + v₀·t . . . . . . where v₀ is the initial vertical velocity in ft/s
For v₀ = 224, this becomes
... h(t) = -16t² + 224t
And this can be rewritten in vertex form as
... h(t) = -16(t² + 14t)
... h(t) = -16(t² + 14t +7²) +16·7² . . . . . complete the square (add the square of half the t coefficient inside parentheses; add the opposite of that amount outside parentheses)
... h(t) = -16(t +7)² + 784
The vertex of this downward-opening parabola is (7, 784), so ...
The rocket reaches its maximum height at 7 seconds.
The maximum height of the rocket is 784 feet.