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nordsb [41]
2 years ago
5

The Bobcats football coach logged the following yardage gains and losses over four plays of a game.

Mathematics
1 answer:
lions [1.4K]2 years ago
5 0
Answer:
9.8x - 11.1x
Explanation:
25 - 5.2 = 9.8x
0.9 - 12 = -11,1y

Notice: I’m not sure but if it wrong, you could replaced with 10x - 11y which be better answer
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Points A (3,8) and B (-4,8 are located on a cooridinate plane. Find the distance between them.
aleksandrvk [35]
-4 + 3 = 7
8=8
(7,0) = DISTANCE BETWEEN THEM 
7 0
3 years ago
Slope = 1.75; (10, 16.5)
vazorg [7]
Do you want the equation of the line given the slope and a point it goes through?

y - y1 = m (x - x1)
y - 16.5 = 1.75 (x - 10)
y - 16.5 = 1.75x -17.5
y = 1.75x - 1
8 0
3 years ago
Which is an equivalent to to 752<br> O 1412<br> 021-10<br> 021-15
Stella [2.4K]
The answer to this equation is 1412 or 21-15
6 0
3 years ago
Read 2 more answers
How do you do estimate of percent problems?
vovangra [49]
How ever many times it goes into 100
4 0
2 years ago
A researcher wants to test whether a certain sound will make rats do worse on learning tasks. It is known that an ordinary rat c
AveGali [126]

Answer:

So we reject the null hypothesis and accept the alternate hypothesis that rats learn slower with sound.

Step-by-step explanation:

In this data we have

Mean= u = 18

X= 38

Standard deviation = s= 6

1) We formulate the null and alternate hypothesis as

H0:  u = 18  against           Ha : u > 18  One tailed test .

2) The significance level alpha = ∝= 0.05 and  Z alpha has a value ± 1.645 for one tailed test.

3)The test statistics used is

Z= X- u / s

z= 38-18/6= 3.333

4) The calculated value of z = 3.33 is greater than the z∝ = 1.645

5) So we reject the null hypothesis and accept the alternate hypothesis that rats learn slower with sound.

First we set the criteria for determining the true of value of the variable. That whether the rats learn in less or more than 18 trials.

Then we find the value of z for the given significance value given and the test about to be checked.

Then the test statistic is determined and calculated.

Then both value of z and z alpha re compared. If the test statistics falls in the rejection region  reject the null hypothesis and conclude alternate hypothesis is true.

The figure shows that the calulated z value lies outside the given z values

4 0
2 years ago
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