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kykrilka [37]
3 years ago
13

What is the volume of a brick that is 20.3 cm long, 8.9 cm wide, and 5.7 cm high?

Mathematics
2 answers:
Anvisha [2.4K]3 years ago
7 0

Answer: 1,029.819 cm³

Step-by-step explanation: In this problem, we're asked to find the volume of a brick. To find the volume of a brick, we use the formula for the volume of a rectangular prism.

To find the volume of a rectangular prism or a prism whose base is a rectangle, we use the following formula.

<em>Volume = length × width × height</em>

Since the brick has a length of 20.3 centimeters, a width of 8.9 centimeters, and a height of 5.7 centimeters, we can plug this information into the formula.

Volume = (20.3 cm) (8.9 cm) (5.7 cm)

Volume = 1,029.819

Therefore, the volume of the brick is 1,029.819 cm³.

Also, it's important to understand that we can plug any number in for the length width or height as long as it's one of the numbers given and it's not used more than once.

This is because the commutative property of multiplication tells us that changing the order of the factors doesn't change the product.  

Anvisha [2.4K]3 years ago
4 0

Answer:

1029.819

Step-by-step explanation:

20.3 * 8.9 * 5.7 = 1029.819

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MArishka [77]
Is the answer 240.is that one of your options
5 0
3 years ago
I need help with 25.
noname [10]

Sum of linear pair of angles = 180°

so

<EFG + <GFH = 180°

2n + 21 + 4n + 15 = 180°

6n + 36 = 180°

6n = 144

n = 24

<EFG = 2(24) + 21 = 69°

<GFH = 4n + 15 = 4(24) + 15 = 111°

6 0
3 years ago
40 is what percent of 32?
Daniel [21]

Answer:

125%

Step-by-step explanation:

Is means equals and of means multiply

40 = P * 32  where P is in decimal form

Divide each side by 32

40/32 = P

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Now change to percent form ( multiply by 100)

125%

7 0
3 years ago
Read 2 more answers
Help... It's homework, I need ur Help :""""")​
pochemuha

Answer:

112

Step-by-step explanation:

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6 0
3 years ago
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Simora [160]
Surface area is just the area of all these 4 triangles plus the rectangle.

First we can find the area of the rectangle.

\sf A=lw

Half of the length is 28 cm, so the full length must be 28 * 2 = 56 cm.

\sf A=(56)(27)

\sf A=1512cm^2

The base for the left and right triangles are 27. The heights would be the net length minus half the length of the rectangle:

\sf 82.8-28=54.8\? cm

Calculate the area:

\sf A=\dfrac{1}{2}bh

\sf A=\dfrac{1}{2}(27)(54.8)

\sf A=739.8\?cm^2

We have two of these triangles.

\sf 739.8\times 2=1479.6\? cm^2

Now do the other two pair of triangles. The bases for them are 28 + 28 = 56 cm. The heights would be the net width minus the width of the rectangle:

\sf 81.2-27=54.2\?cm

Now find the area:

\sf A=\dfrac{1}{2}bh

\sf A=\dfrac{1}{2}(56)(54.2)

\sf A=1517.6\? cm^2

We have two of these triangles.

\sf 1517.6\times 2=3035.2\?cm^2

Add all the areas together:

\sf 1512+1479.6+3035.2=\boxed{\sf 6026.80\? cm^2}
7 0
3 years ago
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