Maybe 4 are quarters, im not actually sure
Answer:
D
Step-by-step explanation:
![4=r cos \theta\\-4=r sin \theta\\square ~and~add\\16+16=r^2(cos^2 \theta+sin^2\theta)\\r^2=32\\ r=4\sqrt{2} \\divide \\tan \theta=-1\\as x is positive ,y is negative ,so \theta lies in 4th quadrant.\\tan \theta=-1=-tan 45=tan(360-45)=tan 315\\\theta=315°\\\\co-ordinates~ are~(r,theta) ~or~(-r,\theta+ -180°)\\hence ~co-ordinates~are(4\sqrt{2} ,315°),(-4\sqrt{2} ,135°)](https://tex.z-dn.net/?f=4%3Dr%20cos%20%5Ctheta%5C%5C-4%3Dr%20sin%20%5Ctheta%5C%5Csquare%20~and~add%5C%5C16%2B16%3Dr%5E2%28cos%5E2%20%5Ctheta%2Bsin%5E2%5Ctheta%29%5C%5Cr%5E2%3D32%5C%5C%20r%3D4%5Csqrt%7B2%7D%20%5C%5Cdivide%20%5C%5Ctan%20%5Ctheta%3D-1%5C%5Cas%20x%20is%20positive%20%2Cy%20is%20negative%20%2Cso%20%5Ctheta%20lies%20in%204th%20quadrant.%5C%5Ctan%20%5Ctheta%3D-1%3D-tan%2045%3Dtan%28360-45%29%3Dtan%20315%5C%5C%5Ctheta%3D315%C2%B0%5C%5C%5C%5Cco-ordinates~%20are~%28r%2Ctheta%29%20~or~%28-r%2C%5Ctheta%2B%20-180%C2%B0%29%5C%5Chence%20~co-ordinates~are%284%5Csqrt%7B2%7D%20%2C315%C2%B0%29%2C%28-4%5Csqrt%7B2%7D%20%2C135%C2%B0%29)
The answer is 105 4/61
If you do the long division correctly, you will get 105 and all you have is 4 left.
Since you are dividing by 61, you do 4/61.
So that is how you get 105 4/61
I hope this helps!
Answer:
30 cm^3
Step-by-step explanation:
Given
radius for both shape = r
height for both shape = h
volume of cylinder is given by ![\pi r^2h](https://tex.z-dn.net/?f=%5Cpi%20r%5E2h)
volume of cone is given by ![1/3(\pi r^2h)](https://tex.z-dn.net/?f=1%2F3%28%5Cpi%20r%5E2h%29)
From above two equation we can see that
is volume of cylinder
thus we can say that volume of cone is 1/3(volume of cylinder)
So we can say that for any cylinder and cone whose height is same and base is congruent
volume of cone will be one-third of volume of cylinder.
Now in given problem
volume of cylinder is 90 cm^3
So , volume of given cone will be one-third of 90 cm^3
which is 1/3*90 cm^3 = 30 cm^3.
Thus, volume of the given cone is 30 cm^3.
Please mark it the brainliest