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Ket [755]
2 years ago
8

What is one effective way for employees to keep their skillsets current?

Computers and Technology
2 answers:
natali 33 [55]2 years ago
6 0

The correct answer is B. Read journals online or subscribe to them

I got this answer correct

lys-0071 [83]2 years ago
4 0
They are probably looking for B.  subscribing to journals is a good way of keeping up with what's happening in any field.

Of course, a very carefully curated professional network online is great for this too (but they said "personal" so that's not the answer)

Employers generally prefer that employees WORK as often as possible, so even though JUDICIOUS use of social media is a great way to keep current, D isn't the answer either.

Blogging about personal experiences is not necessarily going to teach you anything about work, though blogging professionally can be useful in gathering response from your readership
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You are to calculate the property tax for tax payers. You will ask the county tax clerk if they want to run the program and init
andre [41]

Answer:

Explanation:

The following code is written in Java. It creates the loop as requested and validates the information provided before continuing, if the information is invalid it prints "Invalid Information to the screen" and asks the user to enter the information again. Finally, outputing all the requested information at the end of the program. The code has been tested and the output can be seen in the attached image below.

import java.util.ArrayList;

import java.util.Arrays;

import java.util.Scanner;

class Brainly {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       int totalValues = 0;

       int totalTaxes = 0;

       int count = 0;

       while(true) {

           int lotNumber, value;

           double tax;

           System.out.println("Would you like to add an Entry: 1=Yes 0=No");

           int answer = in.nextInt();

           if (answer == 1) {

               System.out.println("Please enter lot number: ");

               lotNumber = in.nextInt();

               if ((lotNumber >= 0) && (lotNumber <= 999999)) {

                   System.out.println("Please enter assessed value: ");

                   value = in.nextInt();

                   tax = value * 0.05;

                   System.out.println("Lot Number: " + lotNumber);

                   System.out.println("Property Value: " + value);

                   System.out.println("Property Tax: " + tax);

                   totalTaxes += tax;

                   totalValues += value;

                   count += 1;

               } else {

                   System.out.println("Invalid Lot Number");

               }

           } else {

               break;

           }

       }

       int average = totalTaxes / count;

       System.out.println("Total Property Values: " + totalValues);

       System.out.println("Total Property Taxes: " + totalTaxes);

       System.out.println("Average Property Tax" + average);

   }

}

8 0
2 years ago
Suppose there are 69 packets entering a queue at the same time. Each packet is of size 7 MiB. The link transmission rate is 1.7
svp [43]

Answer:

69.08265412 milliseconds

Explanation:

Lets first convert 7 MiB to bits

7*1024*1024*8=58720256 bits

Now convert bits to Gbits

58720256/10^{9}  =0.058720256 Gbits

Queuing Delay = Total size/transmission link rate

Queuing Delay= \frac{0.058720256}{1.7} =0.03454132706 seconds

Delay of packet number 3 = 0.03454132706*2=0.06908265412 seconds

or 0.06908265412= 69.08265412 milliseconds

7 0
3 years ago
In some video games, the player cannot obtain the reward without doing what with something that they already have?
Crank

Answer:

risking

Explanation:

8 0
2 years ago
Why a design that doesn't fail initially fails after some time/use? identify at least 3 such mechanisms?
alina1380 [7]
Runs out of memory
has uninitialized    variables
uses  undefined behaviour

4 0
3 years ago
(tco 7) the asp.net ajax client-side framework is loaded on the _____ for an asp.net web application.
jok3333 [9.3K]

a client-side framework is loaded on the client side, ie., the browser.

4 0
2 years ago
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