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Ket [755]
2 years ago
8

What is one effective way for employees to keep their skillsets current?

Computers and Technology
2 answers:
natali 33 [55]2 years ago
6 0

The correct answer is B. Read journals online or subscribe to them

I got this answer correct

lys-0071 [83]2 years ago
4 0
They are probably looking for B.  subscribing to journals is a good way of keeping up with what's happening in any field.

Of course, a very carefully curated professional network online is great for this too (but they said "personal" so that's not the answer)

Employers generally prefer that employees WORK as often as possible, so even though JUDICIOUS use of social media is a great way to keep current, D isn't the answer either.

Blogging about personal experiences is not necessarily going to teach you anything about work, though blogging professionally can be useful in gathering response from your readership
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In the ADT graph the methid addVertex has efficiency
sweet-ann [11.9K]

Answer:

In ADT graph the efficiency of addVertex has efficiency O(logn).

Explanation:

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hence we conclude that the answer is O(logn).

6 0
2 years ago
Write a lottery program that will ask the user if they would like to pick 5 numbers (1-30) or if they would like to choose EZ Pi
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Answer:

Explanation:

The following code is written in Python and creates arrays for the user's numbers and the next chance numbers, it also creates a cost variable and a did_you_win variable. The function takes in the winning numbers as an array parameter. It asks all the necessary questions to generate data for all the variables and then compares the user's numbers to the winning numbers in order to detect if the user has won. Finally, it prints all the necessary information.

import random

def lottery(winning_numbers):

   user_numbers = []

   next_chance_drawing = []

   cost = 0

   did_you_win = "No"

   #print("Would you like to choose your own 5 numbers? Y or N")

   answer = input("Would you like to choose your own 5 numbers? Y or N: ")

   if answer.capitalize() == "Y":

       for x in range(5):

           user_numbers.append(input("Enter number " + str(x+1) + ": "))

   else:

       for x in range(5):

           user_numbers.append(random.randint(0,31))

           cost += 1

   next_chance = input("Would you like to enter a Next Chance drawing for $1.00? Y or N: ")

   if next_chance.capitalize() == "Y":

       for x in range(4):

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           cost += 1

           

   if user_numbers == winning_numbers or next_chance_drawing == winning_numbers:

       did_you_win = "Yes"

   print("User Numbers: " + str(user_numbers))

   print("Next Chance Numbers: " + str(next_chance_drawing))

   print("Cost: $" + str(cost))

   print("Did you win: " + did_you_win)

6 0
2 years ago
What is the name of the technology that is typically implemented on switches to avoid Ethernet connectivity problems when the wr
Andrew [12]

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Explanation:

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3 years ago
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abruzzese [7]

Answer:

Following is given the solution of your question as required.

All the necessary descriptions are given in form of comments,

Sample output are also shown.

I hope it will help you!

Explanation:

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Oksana_A [137]

Answer:

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