Answer:
163 units ^2
Step-by-step explanation:
I assume you are looking for area.
split the block into two blocks, one is 11 x (17-4)
the other blocks is 4x5
large block is 11*13 = 143
small block is 4*5=20
total area is 143 + 20 = 163 units ^2
Answer:
I have to say, I was a bit stumped on this one for some reason, but I believe your answer is y^2.
Step-by-step explanation:
All four variables , (14, 15, y^2, & y^4) should all have a common denominator, but I only see similarities in y^2 with y^4 and 14 with 15, but the y's can be understood ones. Multiply your common variables and get y^2. Could someone check me in that though?
A whole number is a number that is whole as in 1,2,3,4,etc, they don’t have decimals. To find the whole number for these questions you must look at the places (hundreds, thousands, ten thousands.) I was always told a trick which is 4 or less let it rest, 5 or more let it sore. (Basically if it’s less than 4 then decrease it, if it’s higher than increase it.)
12.496 = 13
2.90 = 3
Your answers are 13 and 3.
Answer:
Orion's belt width is 184 light years
Step-by-step explanation:
So we want to find the distance between Alnitak and Mintaka, which is the Orions belts
Let the distance between the Alnitak and Mintaka be x,
Then applying cosine
c²=a²+b²—2•a•b•Cosθ
The triangle is formed by the 736 light-years and 915 light years
Artemis from Alnitak is
a = 736lightyear
Artemis from Mintaka is
b = 915 light year
The angle between Alnitak and Mintaka is θ=3°
Then,
Applying the cosine rule
c²=a²+b²—2•a•b•Cosθ
c² =736² + 915² - 2×, 736×915×Cos3
c² = 541,696 + 837,225 - 1,345,034.1477702404
c² = 33,886.85222975954
c = √33,886.85222975954
c = 184.0838184897 light years
c = 184.08 light years
So, to the nearest light year, Orion's belt width is 184 light years