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PtichkaEL [24]
2 years ago
8

Solve the equation. 4(z – 3) = 22

Mathematics
2 answers:
Keith_Richards [23]2 years ago
7 0
Z=6 just trust me on this lol
Brrunno [24]2 years ago
4 0

Answer: z=6

Step-by-step explanation:

4(z-3)=2z

4z-12=2z subtract 2z from both sides

2z-12=0 add 12 to both sides

2z=12 divide 2 to both sides

z=6

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On every 3rd day Ivan goes to the gym to exercise. Every 5th day Gavin goes to the gym to exercise. What is the first day Ivan a
Colt1911 [192]
You have to find the LCM (least common multiple) of both numbers.

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ivan and gavin will be together at the gym on the 15th day.
8 0
3 years ago
Read 2 more answers
Help me please!!!!!!!!!!!!!!!!
Sav [38]

Answer:

x=-4 and y=4

Step-by-step explanation:

(6x+9y)-(6x+7y)=12-4=8

--> 9y-7y=8

-->2y=8-->y=4

-->6x+7×4=4  -->x=-4

7 0
2 years ago
Read 2 more answers
Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t
LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

(5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6)  =\dfrac{20}{36}

The probability distribution of this event is given as follows.

\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|

First, we determine the expected Value of this event.

Expected Value

=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

Probability of Winning  =\dfrac{20}{36}

If the game is played 100 times

Number of times expected to win

=\dfrac{20}{36} \times 100\\=56$ times

Therefore, number of times expected to loose

= 100-56

=44 times

8 0
3 years ago
Plz help me its confusing
IgorC [24]

Answer:

Step-by-step explanation:

A

8 0
3 years ago
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