Solve for x 14 -2x = \frac{3 + x}{2}

Expand<br> c(3c - 3)<br> I need help on this

Rudik [331]

$\\ \sf\longmapsto c(3c-3)$

Apply distributive law

a(b-d)=ab-ad

$\\ \sf\longmapsto 3c(c)-3(c)$

$\\ \sf\longmapsto 3c^2-3c$

We can still take common

$\\ \sf\longmapsto 3c(c-1)$

4 0

2 years ago

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Clarence set his watch 16 seconds behind , and it falls behind 2 seconds every day . How many days behind has it been since Clar

harkovskaia [24]

Answer:

15 days.

Step-by-step explanation:

46 - 16 = 30.

It falls 2 seconds behind each day so the number of required days

= 30 / 2 = 15.

7 0

3 years ago

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50 POINTS!PLEASE HELP

Mamont248 [21]

Step-by-step explanation:

For no 1...

The range is [ -9, -7, 1]

For no 2....

The range is [-12, -10, -2]

For no 3.....

The range is [-11, -8, 4]

4 0

3 years ago

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Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

A(-4, 4)

B(2, 5)

Finding the length of AB using the formula

$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

$=\sqrt{37}$

$d_{AB}\:=\sqrt{37}$

$d_{AB}=6.08$ units

Given the vertices of the segment JK

J(2, 2)

K(7, 2)

From the graph, it is clear that the length of JK = 5 units

so

$d_{JK}=5$ units

Given the vertices of the segment GH

G(-5, -2)

H(-2, -2)

Finding the length of GH using the formula

$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

$d_{JK}=5$

$d_{GH}\:=\:3$

Thus,

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0

2 years ago

Juan pulled a red card from the deck of regular playing cards. This probability is 2652 or 12 . He puts the card back into the d

kenny6666 [7]

Answer:

no

Step-by-step explanation:

if he randomly pulls it out it's still the same number of red cards and also the total number of cards as always

can't change

6 0

2 years ago

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