Problem 1
With limits, you are looking to see what happens when x gets closer to some value. For example, as x gets closer to x = 2 (from the left and right side), then y is getting closer and closer to y = 1/2. Therefore the limiting value is 1/2
Another example: as x gets closer to x = 4 from the right hand side, the y value gets closer to y = 4. This y value is different if you approach x = 0 from the left side (y would approach y = 1/2)
Use examples like this and you'll get the results you see in "figure 1"
For any function values, you'll look for actual points on the graph. A point does not exist if there is an open circle. There is an open circle at x = 2 for instance, so that's why f(2) = UND. On the other hand, f(0) is defined and it is equal to 4 as the point (0,4) is on the function curve.
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Problem 2
This is basically an extension of problem 1. The same idea applies. See "figure 2" (in the attached images) for the answers.
Answer: around 0.0064
i rounded it to the nearest hundred thousandth because the number will keep going on forever.
Answer:

Step-by-step explanation:
The formula for the circumference of a circle with the diameter is:

Since the diameter is 3m, solve for
:

Answer:
278.64cm²
Step-by-step explanation:
Area of the sheet left out = Area of the square - Area of the 9 circles
Area of the square = L^2
L is the side length of the square
A = 36^2
Area of the square = 1296cm^2
Diameter of a circle = 38/3 = 12cm
Area of a circle = πr²
r is the radius = 12/2 = 6cm
Area of a circle = 3.14(6)²
Area of a circle = 3.14 * 36
Area of a circle = 113.04cm²
Area of 9 circles = 9 * 113.04
Area of 9 circles = 1,017.36cm²
Area of the left over = 1296 - 1,017.36
Area of the left over = 278.64cm²