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3 years ago

Find the inverse function? I need help.

Mathematics

1 answer:

Tatiana [17]3 years ago

6 0

Super easy. Take the function, and replace X with Y and Y with X. For example, if Y=12/x, then the inverse would be X=12/Y. Now solve for Y, so XY=12, the Y=12/x.

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On a math test 12 students earned an a this number is exactly 25% of the total number of students in the class how many students

statuscvo [17]

Answer:

48 students.

Step-by-step explanation:

25% of total students = 12

suppose,

total students= x

so,

25% of x=12

(25/100)*x=12

25*x=(12*100)

x=1200/25

x=48

therefore,

x= total students= 48.

7 0

3 years ago

Y=f(x) = 8^x find f(x) when x= 1/3

lilavasa [31]

the correct answer for plato users is

2!!

4 0

3 years ago

4.) What is the exact value of sinθ when θ lies in Quadrant II and cosθ=−513

dimaraw [331]

Answer:

Part 4) $sin(\theta)=\frac{12}{13}$

Part 10) The angle of elevation is $40.36\°$

Part 11) The angle of depression is $78.61\°$

Part 12) $arcsin(0.5)=30\°$ or $arcsin(0.5)=150\°$

Part 13) $-45\°$ or $225\°$

Step-by-step explanation:

Part 4) we have that

$cos(\theta)=-\frac{5}{13}$

The angle theta lies in Quadrant II

The sine of angle theta is positive

Remember that

$sin^{2}(\theta)+ cos^{2}(\theta)=1$

substitute the given value

$sin^{2}(\theta)+(-\frac{5}{13})^{2}=1$

$sin^{2}(\theta)+(\frac{25}{169})=1$

$sin^{2}(\theta)=1-(\frac{25}{169})$

$sin^{2}(\theta)=(\frac{144}{169})$

$sin(\theta)=\frac{12}{13}$

Part 10)

Let

$\theta$ ----> angle of elevation

we know that

$tan(\theta)=\frac{85}{100}$ ----> opposite side angle theta divided by adjacent side angle theta

$\theta=arctan(\frac{85}{100})=40.36\°$

Part 11)

Let

$\theta$ ----> angle of depression

we know that

$sin(\theta)=\frac{5,389-2,405}{3,044}$ ----> opposite side angle theta divided by hypotenuse

$sin(\theta)=\frac{2,984}{3,044}$

$\theta=arcsin(\frac{2,984}{3,044})=78.61\°$

Part 12) What is the exact value of arcsin(0.5)?

Remember that

$sin(30\°)=0.5$

therefore

$arcsin(0.5)$ -----> has two solutions

$arcsin(0.5)=30\°$ ----> I Quadrant

$arcsin(0.5)=180\°-30\°=150\°$ ----> II Quadrant

Part 13) What is the exact value of $arcsin(-\frac{\sqrt{2}}{2})$

The sine is negative

The angle lies in Quadrant III or Quadrant IV

Remember that

$sin(45\°)=\frac{\sqrt{2}}{2}$

therefore

$arcsin(-\frac{\sqrt{2}}{2})$ ----> has two solutions

$arcsin(-\frac{\sqrt{2}}{2})=-45\°$ ----> IV Quadrant

$arcsin(-\frac{\sqrt{2}}{2})=180\°+45\°=225\°$ ----> III Quadrant

5 0

3 years ago

. Mark has $20 in his bank account. He saves $5 each week. How much money does Mark have in his account after 9 weeks? Use x to

DanielleElmas [232]

Answer:

$135

Step-by-step explanation:

id k how to explain but since he saves 5 dollars he basically has 15 dollars in his bank account u just need to multiply 15 with however many weeks he saves up for

5 0

3 years ago

Anna baked 3 batches of cookies with c cookies in each batch. She then ate 8 cookies! How many cookies does Anna have left? Writ

borishaifa [10]

Answer:

$3c-8$