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2 years ago

If Kamina can do a job in 43 hours and Simon and Kamina working together can do the same job in 15 hours, find how

Mathematics

1 answer:

jenyasd209 [6]2 years ago

5 0

Answer:

645/28 hours

Step-by-step explanation:

In 1 hour, Kamina does 1/43 of the job.

Simon takes x hour to do the job alone.

In 1 hour, Simon does 1/x of the job.

Together, they do the job is 15 hours, so in 1 hour, they do 1/15 of the job.

1/43 + 1/x = 1/15

15x/(645x) + 645/(645x) = 43x/(645x)

15x + 645 = 43x

28x = 645

x = 645/28

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Step 1: 4t - 3 > 37t - 50

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2 years ago

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3 years ago

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2 years ago

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lara [203]

Yes you have a good example.

x = number of cookies

2*x = total amount spent on cookies at $2 each

2x-3 = amount you pay after the $3 discount is applied one time for the entire order

-------------

a more numeric example may be this

Lets say you bought 12 cookies, so x = 12

This means it costs 2*x = 2*12 = 24 dollars total if the discount doesnt apply

However, the 3 dollar discount is there, so the grand total is 24-3 = 21 dollars.

3 0

3 years ago

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3 years ago