Is there a way that you could show me the table so I can help you please?
Answer:
Step-by-step explanation:
That '5' in f(5x) will compress the graph of x^2 horizontally.
If you were to graph f(x) = x^2, you'd get a parabolic graph; the parabola will open UP.
Suppose you graphed f(x) = x^2 on the interval [-4, 4].
Then the graph of g(x) = f(5x) would be graphed on the interval [-4/5, 4/5]. In other words, the graph would be on a shorter interval, one shorter by a factor of 5.
So, r' (the new r) becomes kr, and h'=h*k,
so V' = pi * (r')^2*h' = pi * (r*k)^2*(h*k) = pi*r^2*h*k^3 = V * k^3
Convinced?
2√72 / √8 ± √2
If the denominator is √8 + √2,
2√72 / √8 + √2
= 2√(2*2*2*3*3) / √(2*2*2) + √2
= 2*2*3√2 / 2√2 + √2
= 12√2 / 3√2
= 4
Answer:
y = 3
Step-by-step explanation:
Let's start with the left side of the equation.
5(y-2)-2= 2(y+1)-5
5y-10-2= 2(y+1)-5
Now let's solve the right side
5y-10-2= 2y+2-5
5y-12= 2y-3
-2y -2y
3y-12=-3
+12 +12
3y = 9
3y/3 = 9/3
y = 3
hope this helps!
