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nordsb [41]
3 years ago
11

What number is 2 times the difference between 6 &3? PLEASE BRAKE DOWN ANSWER!!

Mathematics
1 answer:
Orlov [11]3 years ago
8 0

The answer is x = 2 (6-3). This is because x equals 2 times, or doubling the product of 6 - 3.

x = 2 (6-3)

x = 2 (3)

x = 6

Hope this helped! <3

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What is 6 increased by y
nadya68 [22]
6+y

Since increased (key word) means addition.
3 0
3 years ago
The length of a rectangle is 5 times the width. If the perimeter is to be greater than 36 meters. What are the possible values f
Lostsunrise [7]

Answer:

  The width must be greater than 3 meters.

Step-by-step explanation:

Let w represent the width. Then 5w will represent the length, which is 5 times the width. The perimeter is the total of the side lengths of the rectangle, so is ...

  P = 2w + 2(5w) = 12w

We want this to be greater than 36 m, so ...

  P > 36 m

  12w > 36 m . . . . . . . substitute our expression for P

  w > 3 m . . . . . . . . . . divide by 12

The possible values for width are those values that are more than 3 meters.

3 0
3 years ago
98, 78, 84, 75, 91<br> What is the mean absolute deviation of his scores?
Inessa [10]

Answer:

85.2

Step-by-step explanation:

you add all the numbers together then you divide it by 5 then you have your answer.

8 0
3 years ago
Derive the equation of the parabola with a focus at (3,1) and a directrix of y = 5
serg [7]
So hmmm  check the picture below

so... the vertex is "p" distance from the focus and the directrix, thus, the vertex is really half-way between both

in this case, 2 units up from the focus or 2 units down from the directrix, and thus it lands at 3,3

now, the "p" distance is 2, however, the directrix is up, the focus point is below it, the parabola opens towards the focus point, thus, the parabola is opening downwards, and the squared variable is the "x"

because the parabola opens downwards, "p" is negative, and thus, -2

now, let's plug all those fellows in then

\bf \begin{array}{llll}&#10;(x-{{ h}})^2=4{{ p}}(y-{{ k}})\\&#10;\end{array}&#10;\qquad &#10;\begin{array}{llll}&#10;vertex\ ({{ h}},{{ k}})\\&#10;{{ p}}=\textit{distance from vertex to }\\&#10;\qquad \textit{ focus or directrix}&#10;\end{array}\\\\&#10;-----------------------------\\\\&#10;&#10;\begin{cases}&#10;h=3\\&#10;k=3\\&#10;p=-2&#10;\end{cases}\implies (x-3)^2=4(-2)(y-3)\implies (x-3)^2=-8(y-3)&#10;\\\\\\&#10;-\cfrac{(x-3)^2}{8}=y-3\implies \boxed{-\cfrac{1}{8}(x-3)^2+3=y}

5 0
3 years ago
At HD Sport &amp; Fitness gym, analysis shows that, as the demand of the gym, the number of members is 83 when annual membership
gayaneshka [121]

The price at which revenue is maximized is $ 157, and maximum annual revenue is $ 6751.

Since at HD Sport & Fitness gym, analysis shows that, as the demand of the gym, the number of members is 83 when annual membership fee is $ 17 per member and the number of members is 81 when annual membership fee is $ 24 per member, and the number of members and membership fee have a linear relationship, to determine at what membership price is the maximized revenue, and what is the maximum annual revenue, the following calculations must be performed:

  • 17 x 83 = 1411
  • 24 x 81 = 1944
  • 31 x 79 = 2449
  • 38 x 77 = 2926
  • 66 x 69 = 4554
  • 73 x 67 = 4891
  • 80 x 65 = 5200
  • 94 x 61 = 5734
  • 101 x 59 = 5959
  • 122 x 53 = 6466
  • 129 x 51 = 6579
  • 150 x 45 = 6750
  • 157 x 43 = 6751
  • 164 x 41 = 6724

Therefore, the price at which revenue is maximized is $ 157, and maximum annual revenue is $ 6751.

Learn more in brainly.com/question/11663530

4 0
2 years ago
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