Increasing the sample size by a factor of 4 or multiplying
it by 4 is equal to increasing the standard error by 1/2. Therefore, the
interval will be half as varied. This also works almost for population
averages as lengthy as the multiplier from the t-curve doesn't modify much when
increasing the sample size.
Answer:
Step-by-step explanation:
From the given information,
Suppose
X represents the Desktop computer
Y represents the DVD Player
Z represents the Two Cars
Given that:
n(X)=275
n(Y)=455
n(Z)=405
n(XUY)=145
n(YUZ)=195
n(XUZ)=110
n((XUYUZ))=265
n(X ∩ Y ∩ Z) = 1000-265
n(X ∩ Y ∩ Z) = 735
n(X ∪ Y) = n(X)+n(Y)−n(X ∩ Y)
145 = 275+455 - n(X ∩ Y)
n(X ∩ Y) = 585
n(Y ∪ Z) = n(Y) + n(Z) − n(Y ∩ Z)
195 = 455+405-n(Y ∩ Z)
n(Y ∩ Z) = 665
n(X ∪ Z) = n(X) + n(Z) − n(X ∩ Z)
110 = 275+405-n(X ∩ Z)
n(X ∩ Z) = 570
a. n(X ∪ Y ∪ Z) = n(X) + n(Y) + n(Z) − n(X ∩ Y) − n(Y ∩ Z) − n(X ∩ Z) + n(X ∩ Y ∩ Z)
n(X ∪ Y ∪ Z) = 275+455+405-585-665-570+735
n(X ∪ Y ∪ Z) = 50
c. n(X ∪ Y ∪ C') = n(X ∪ Y)-n(X ∪ Y ∪ Z)
n(X ∪ Y ∪ C') = 145-50
n(X ∪ Y ∪ C') = 95
Find the total of oranges
total = 16 × 185
total = 2960
Find how many packs
pack = 2960/5
pack = 592
There are 592 packs of oranges
Answer:
I believe 0.75 is the answer. Here is my work:
Step-by-step explanation:
1. 250 divided by 5 = 50 (this is to get 1/5 of 250)
2. 250 divided by 2 (because 1/2 is equivalent to 50% of the overall number) = 125
3. 50 + 125 = 175
4. 250-175 = 75
5. 75 can be converted to 0.75 as a decimal by moving 2 digits over.
Therefore, out of the 250 seventh grade students, 0.75 are in other electives.
Also, I'm in 7th grade so this is my work, I'm sure there are other ways of solving this, too. Please do not add this answer if you don't believe I'm right.
Thanks for your time, and have a nice day! : )
Answer: 0.75
